Php html javascript中的按钮不工作
我试图提交一个表单来执行php脚本。但是“提交”按钮不起作用。我似乎没有遗漏任何引号或表达式。我做错了什么问题Php html javascript中的按钮不工作,php,html,button,Php,Html,Button,我试图提交一个表单来执行php脚本。但是“提交”按钮不起作用。我似乎没有遗漏任何引号或表达式。我做错了什么问题 <script type="text/javascript"> function doSubmit() { <?php echo "Hello"; ?> var actions = document.frm.actions.value; var tables = document.frm.tables.value; var text0 = document.
<script type="text/javascript">
function doSubmit()
{
<?php
echo "Hello";
?>
var actions = document.frm.actions.value;
var tables = document.frm.tables.value;
var text0 = document.frm.text0.value;
var text1 = document.frm.text1.value;
var text2 = document.frm.text2.value;
/*var txtBox = document.getElementById("text3");
if (txtBox!=null){
var text3 = document.frm.text3.value;
var strURL = "devicesql.php?actions=" +actions+ "&tables=" +tables+ "&text0=" +text0+ "&text1=" +text1+ "&text2=" +text2+ "&text3=" +text3;
}
else
{*/
var strURL = "devicesql.php?actions=" +actions+ "&tables=" +tables+ "&text0=" +text0+ "&text1=" +text1+ "&text2=" +text2;
//}
var xmlhttp;
if (str=="")
{
document.getElementById("result").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{
xmlhttp=new XMLHttpRequest();
}
else
{
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("result").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET",strURL,true);
xmlhttp.send(null);
}
</script>
<form name="frm" method="get" action="doSubmit();">
<?php
// Connect to server and select database.
mysql_connect("127.0.0.1:3306", "root", "")or die("cannot connect");
mysql_select_db("PushApplication")or die("cannot select DB");
$sql="SELECT * FROM Device";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td><form name="form1" method="post" action="">
<table width="400" border="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td align="center" bgcolor="#FFFFFF">#</td>
<td align="center" bgcolor="#FFFFFF"><strong>ID</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>DeviceID</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>DeviceType</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>Description</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>OS_Version</strong></td>
<td align="center" bgcolor="#FFFFFF"><strong>Status</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['ID']; ?>"></td>
<td bgcolor="#FFFFFF"><? echo $rows['ID']; ?></td>
<td bgcolor="#FFFFFF"><? echo $rows['DeviceID']; ?></td>
<td bgcolor="#FFFFFF"><? echo $rows['DeviceType']; ?></td>
<td bgcolor="#FFFFFF"><? echo $rows['Description']; ?></td>
<td bgcolor="#FFFFFF"><? echo $rows['OS_Version']; ?></td>
<td bgcolor="#FFFFFF"><? echo $rows['Status']; ?></td>
</tr>
<?php
}
?>
<tr>
<td colspan="7" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td>
</tr>
<?php
// Check if delete button active, start this
if($delete){
for($i=0;$i<$count;$i++){
$del_id = $checkbox[$i];
$sql = "DELETE FROM Device WHERE ID='$del_id'";
$result = mysql_query($sql);
}
// if successful redirect to delete_multiple.php
if($result){
echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete_multiple.php\">";
}
}
mysql_close();
?>
</table>
</form>
</td>
</tr>
</table>
<br />
<br />
Action: <id="actions">
<select name="actions">
<option value="insert into ">Insert</option>
<option value="update">Update</option>
<option value="select">Display</option>
</select>
</br>
</br>
Database Table Name: <id="tables">
<select name="tables" onchange="addRows(this.value)">
<option>Select Table</option>
<option value="Applications">Application</option>
<option value="Device">Device</option>
</select>
</br>
<div id="addedRows"></div>
</br>
<input type="submit" value="Submit" onclick="doSubmit()">
</br>
</br>
Result: <div id="result"></div>
</form>
函数doSubmit()
{
var actions=document.frm.actions.value;
var tables=document.frm.tables.value;
var text0=document.frm.text0.value;
var text1=document.frm.text1.value;
var text2=document.frm.text2.value;
/*var txtBox=document.getElementById(“text3”);
如果(txtBox!=null){
var text3=document.frm.text3.value;
var strURL=“devicesql.php?actions=“+actions+”&tables=“+tables+”&text0=“+text0+”&text1=“+text1+”&text2=“+text2+”&text3=“+text3;
}
其他的
{*/
var strURL=“devicesql.php?actions=“+actions+”&tables=“+tables+”&text0=“+text0+”&text1=“+text1+”&text2=“+text2;
//}
var-xmlhttp;
如果(str==“”)
{
document.getElementById(“结果”).innerHTML=“”;
返回;
}
if(window.XMLHttpRequest)
{
xmlhttp=新的XMLHttpRequest();
}
其他的
{
xmlhttp=新的ActiveXObject(“Microsoft.xmlhttp”);
}
xmlhttp.onreadystatechange=函数()
{
if(xmlhttp.readyState==4&&xmlhttp.status==200)
{
document.getElementById(“结果”).innerHTML=xmlhttp.responseText;
}
}
open(“GET”,strURL,true);
xmlhttp.send(空);
}
#
ID
设备ID
设备类型
说明
OS\U版本
状态
您需要从表单中删除action属性,提交表单的输入应该具有触发函数的onclick属性,而不是submit事件
<form id="theform">
<!-- some input texts.... or something -->
<button onclick="processForm()">Process form</button>
</form>
<script type="text/javascript">
function processForm () {
var form = document.getElementById('theform');
// your stuff
}
</script>
过程形式
函数processForm(){
var form=document.getElementById('theform');
//你的东西
}
PS:您正在创建一个sintax错误,第一个PHP标记回显“Hello”您需要从表单中删除action属性,提交表单的输入应该具有触发函数的onclick属性,而不是submit事件
<form id="theform">
<!-- some input texts.... or something -->
<button onclick="processForm()">Process form</button>
</form>
<script type="text/javascript">
function processForm () {
var form = document.getElementById('theform');
// your stuff
}
</script>
过程形式
函数processForm(){
var form=document.getElementById('theform');
//你的东西
}
PS:您正在创建一个sintax错误,第一个PHP标记回显“Hello”使用以下代码提交表单,而不是提交按钮
<a href="javascript: doSubmit()">Submit</a>
使用以下代码提交表单,而不是“提交”按钮
<a href="javascript: doSubmit()">Submit</a>
尝试为显示数据库信息的表创建另一个表单。您的表单可能与这两个按钮混淆 尝试为显示数据库信息的表创建另一个表单。您的表单可能与这两个按钮混淆 漂亮。我想这就是原因。谢谢你,伙计!美丽的。我想这就是原因。谢谢你,伙计!