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Php google analytics针对特定帐户的凭据无效_Php_Google Analytics_Oauth 2.0_Google Analytics Api - Fatal编程技术网

Php google analytics针对特定帐户的凭据无效

Php google analytics针对特定帐户的凭据无效,php,google-analytics,oauth-2.0,google-analytics-api,Php,Google Analytics,Oauth 2.0,Google Analytics Api,您好,我正在为google analytics使用另一个帐户,并返回一个错误: GDataauthErrorAuthorizationInvalid Credentials 虽然我以前的帐户运行良好。这可能是因为我在注册过程中遗漏了一些东西,有谁能给我一个详细的步骤,让我使用api_key for google analytics v2.4注册oauth 2.0 多谢各位 //returns session token for multiple calls to API function ge

您好,我正在为google analytics使用另一个帐户,并返回一个错误:

GDataauthErrorAuthorizationInvalid Credentials
虽然我以前的帐户运行良好。这可能是因为我在注册过程中遗漏了一些东西,有谁能给我一个详细的步骤,让我使用api_key for google analytics v2.4注册oauth 2.0

多谢各位

//returns session token for multiple calls to API
function get_session_token($onetimetoken) {
    $output = call_api($onetimetoken, "https://www.google.com/accounts/AuthSubSessionToken");

    if(preg_match("/Token=(.*)/", $output, $matches)) {
        $sessionToken = $matches[1];
    } else {
        echo "Error authenticating with Google.";
        exit;
    }

    return $sessionToken;
}

//gets the data
function call_api($sessionToken,$url){
    $curl = curl_init($url);

    curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);  
    if ($_SESSION['authSub']==true){
        $curlheader[0] = sprintf("Authorization: AuthSub token=\"%s\"/n", $sessionToken);
    } else {
        $curlheader[0] = "Authorization: GoogleLogin auth=" . $sessionToken;
    }
    curl_setopt($curl, CURLOPT_HTTPHEADER, $curlheader);

    $response = curl_exec($curl);
    curl_close($curl);

    return $response;       
}

$requrlvisits = sprintf("https://www.googleapis.com/analytics/v2.4/data?ids=ga:%s&dimensions=ga:date&metrics=ga:visits,ga:pageviews,ga:bounces,ga:timeOnSite&start-date=%s&end-date=%s&sort=ga:date&key=%s",$get_profid[9],$date1,$date2,$api_key);
                            // echo $requrlvisits;

                            $visitsxml = call_api($_SESSION['sessionToken'],$requrlvisits);             
                            $visits = parse_data($visitsxml);

                            print_r($visitsxml);

你有没有想过?我对一个类似的问题感到困惑。@Lenwood您必须更新到他们最新的api,并使用Oauth 2.0对用户进行身份验证。他们现在正在使用API_密钥。