Php 将MySQL查询转换为Yii CDbCriteria

我有两张桌子，名字是

新建\u tbl\u主\u站点ID->模型：站点ID

app_tbl_ict_dapot_发电机组->型号：发电机组

我有一个像这样的mysql查询

SELECT A.siteid, B.type, B.status_operations, B.status
FROM new_tbl_master_siteid as A
LEFT JOIN app_tbl_ict_dapot_genset as B
ON A.siteid = B.siteid

我想在此处左键加入siteid列

我正在考虑修改发电机组模型上的CdbCriteria，如何才能使发电机组gridview的数据提供程序也可以使用SiteID模型中的列

发电机组型号标准

$criteria=new CDbCriteria;

        $criteria->compare('id',$this->id);
        $criteria->compare('siteid',$this->siteid,true);
        $criteria->compare('merk',$this->merk,true);
        $criteria->compare('type',$this->type,true);
        $criteria->compare('capacity',$this->capacity,true);
        $criteria->compare('kapasitas_tangki',$this->kapasitas_tangki,true);
        $criteria->compare('status',$this->status,true);
        $criteria->compare('status_operations',$this->status_operations,true);

        return new CActiveDataProvider($this, array(
            'criteria'=>$criteria,

==================

这是下面的关系

class genset extends CActiveRecord
.....
public function relations()
    {
        // NOTE: you may need to adjust the relation name and the related
        // class name for the relations automatically generated below.
         return array(
            'siteids'=>array(self::BELONGS_TO,'SiteID','siteid'),
        );
    }
....

public function search()
    {
        // @todo Please modify the following code to remove attributes that should not be searched.

        $criteria=new CDbCriteria;

        $criteria->compare('id',$this->id);
        $criteria->compare('siteid',$this->siteid,true);
        $criteria->compare('merk',$this->merk,true);
        $criteria->compare('type',$this->type,true);
        $criteria->compare('capacity',$this->capacity,true);
        $criteria->compare('kapasitas_tangki',$this->kapasitas_tangki,true);
        $criteria->compare('status',$this->status,true);
        $criteria->compare('status_operations',$this->status_operations,true);
        $criteria->with = array('siteids.rtp');
        $criteria->compare('siteids.rtp',$this->rtp,true);

        return new CActiveDataProvider($this, array(
            'criteria'=>$criteria,
        ));
    }

和siteid类

class SiteID extends CActiveRecord
.....
public function relations()
    {
        // NOTE: you may need to adjust the relation name and the related
        // class name for the relations automatically generated below.
        return array(
            'gensets'=>array(self::HAS_MANY, 'genset', 'siteid'),   
        );
    }

但我犯了个错误

Relation "rtp" is not defined in active record class "SiteID".

---

rtp是siteid模型中的一个列

Yii实现这一点的方法是通过关系，例如，您应该将关联表的关系添加到您的模型中（如果它还没有），然后您可以直接访问相关模型的属性，例如，如果siteid对象是$model，而关系的名称是“genset”，您可以像这样获得发电机组的状态：$model->genset->status

您要做的第一件事是创建可以像这样完成的模型之间的关系：

public function relations()
{
        return array(
            'genset'=>array(self::HAS_MANY, 'genset', 'siteid'),
        );
}

在模范班。在两个模型中定义关系后，使用

->with

$criteria->with = array('genset');

---

你准备好出发了。但要确保在两个模型中都定义了关系。

你能给我举个例子吗？我试图将状态解析到gridview中，gridview将其称为“dataProvider”=>$model->search（），提供两个表之间的关系，是否是一对多、多对多等？