Php 是否向表中添加用户会话?
我试图将用户会话添加到一个表中,该表在用户填写表单时填写。然后我想只显示他们在主页上创建的表单Php 是否向表中添加用户会话?,php,html,forms,Php,Html,Forms,我试图将用户会话添加到一个表中,该表在用户填写表单时填写。然后我想只显示他们在主页上创建的表单 <?php require_once("/extlib/vdaemon/vdaemon.php"); require_once("./core/config.php"); ?> <html> <head> <style type="text/css"> body { background: #e4e4e4; } .form {
<?php
require_once("/extlib/vdaemon/vdaemon.php");
require_once("./core/config.php");
?>
<html>
<head>
<style type="text/css">
body {
background: #e4e4e4;
}
.form {
width: 600px;
margin: 0 auto;
background: #fff;
padding: 45px;
border: 1px solid #c2c2c2;
}
.error {
color: #AA0000
}
.controlerror {
background-color: #ffffdd;
border: 1px solid #AA0000;
}
.input {
width: 300px;
height: 35px;
margin-left: 10px;
}
</style>
</head>
<body>
<div class="form">
<?php
$msg = $_GET['msg'];
if ( $msg == '1' ) {
echo '<p>Your information was submitted successfully.</p>';
}
?>
<form action="core/process.php" method="post" id="registration" >
<input type="hidden" name="formID" value="Product_Tracker" />
**<input type="hidden" name="id_user" value="$_SESSION['id_user']" />**
<p>Name of product:<input type="text" name="Name of Product" class="input" />
<p>Please select the tests that were done on the product.</p>
<p>In Circuit Test (ICT): Yes: <input type="radio" name="ICT" value="yes" /> No: <input type="radio" name="ICT" value="no" /></p>
<p>Visual Inspection: Yes: <input type="radio" name="Visual Inspection" value="yes" /> No: <input type="radio" name="Visual Inspection" value="no" /></p>
<p>XRAY: Yes: <input type="radio" name="XRAY" value="yes" /> No: <input type="radio" name="XRAY" value="no" /></p>
<p>Automated Optical Inspection (AOI): Yes: <input type="radio" name="AOI" value="yes" /> No: <input type="radio" name="AOI" value="no" /></p>
<!--<p>Checkbox1 <input type="checkbox" name="checkbox" value="checkbox1" /> Checkbox2: <input type="checkbox" name="checkbox" value="checkbox2" /></p>-->
<input type="submit" value="Submit" />
<p>
<a href='access-controlled.php'>Back</a>
</p>
</form>
</div>
</body>
</html>
<?php VDEnd(); ?>
当我在创建表单时查看phpMyAdmin时,id\u用户是$\u SESSION['id\u user'],而不是创建它的用户的名称 您没有回显$\u SESSION['id\u user']的值,请尝试以下操作
<input type="hidden" name="id_user" value="<?php echo $_SESSION['id_user']"; ?> />
我在显示他们创建的mysql\u select\u dbdatabase的表单时遇到问题,$con$结果=mysql\u querySELECT id\u user,product\u Tracker中的产品名称,其中id\u user=$\u SESSION['Name\u of_user'];虽然$row=mysql_fetch_assoc$result{echo$row['Name_of_Product'];echo;我只是想显示_Product的列名,但您应该回答另一个问题,提供更多详细信息,以及您遇到的错误