Php 拉雷维尔：雄辩的“大于”和“小于”

我希望在查询生成器中使用如下数据库查询：

从active=1且已发布的帖子中选择*如下使用['published'，'>='，$now]

或者使用单独的where函数

$now = new Carbon;
$feed = Post::where('active', 1)->where('published','>=', $now)
->take(5)
->get()
->toArray();

雄辩的

  $feed = Post::where('active','=',1)->where('published','<=',$now)->get();

用这个

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请参阅手册：

请打开手册，很容易找到：

$now = new Carbon;
$feed = Post::where('active', 1)->where('published','>=', $now)
->take(5)
->get()
->toArray();

  $feed = Post::where('active','=',1)->where('published','<=',$now)->get();

$feed = Post::where('active',1)
->where('published','<=',$now)
->take(5)
->get()
->toArray();