Php StringRequest响应为空,没有明显的原因
对于我的原始PHP web服务public void onResponseString响应,响应包含以下响应: {成功:1,消息:Spot已成功添加!} 对于我更新的PHP web服务,响应是空的,不存在 在我的浏览器中运行PHP web服务时,我得到以下JSON对象: {success:1,message:Spot已成功添加!,如_id:428} 这是伟大的,但我希望在应用程序中的响应看起来一样 那么:原因是什么?我如何使JSON对象出现在响应中 Java代码 原始web服务PHP:Php StringRequest响应为空,没有明显的原因,php,android,json,android-volley,Php,Android,Json,Android Volley,对于我的原始PHP web服务public void onResponseString响应,响应包含以下响应: {成功:1,消息:Spot已成功添加!} 对于我更新的PHP web服务,响应是空的,不存在 在我的浏览器中运行PHP web服务时,我得到以下JSON对象: {success:1,message:Spot已成功添加!,如_id:428} 这是伟大的,但我希望在应用程序中的响应看起来一样 那么:原因是什么?我如何使JSON对象出现在响应中 Java代码 原始web服务PHP: 对于脚本
对于脚本为什么在web浏览器中显示正确的JSON对象,而在截击响应中却什么都没有,我感到很惊讶 实现在新的web服务PHP中所做工作的更好方法是只执行一个查询,即原始web服务PHP中的查询,并使用 或
根据您用于MySql连接的方法。在$getId查询中,尝试将WHERE子句更改为LATIONE=:lat和LATIONE=:LNGY您的新web服务PHP容易受到sql注入攻击。在SELECT中使用准备好的语句,就像在INSERT中一样。这与你的计划无关problem@ColinGillespie当我回显$getId时,您的解决方案将从纬度=:纬度和经度=:lng限制1的位置提供SELECT id,这将不起作用..因为您无法通过新的web服务获得答案,显然如果$row{失败。@user1736049抱歉:lng应该是:long
public void writeLikedPos(LatLng location) {
double latitude;
double longitude;
try {
latitude = location.latitude; //nullpointer
longitude = location.longitude;
} catch (NullPointerException e) {
System.out.println("Noe gikk galt!");
e.printStackTrace();
return;
}
final String latitudeStr = String.valueOf(latitude);
final String longitudeStr = String.valueOf(longitude);
StringRequest postRequest = new StringRequest(Request.Method.POST, url,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
System.out.println("String response: " +response);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
System.out.println("Error");
}
}) {
@Override
protected Map<String, String> getParams() {
Map<String, String> params = new HashMap<String, String>();
params.put("latitude", latitudeStr);
params.put("longitude", longitudeStr);
return params;
}
};
VolleySingleton.getInstance().addToReqQueue(postRequest);
}
}
<?php
//load and connect to MySQL database stuff
require("config.inc.php");
if (!empty($_POST)) {
//initial query
if(isset($_POST['user_id']) && !empty($_POST['user_id'])) {
$query = "INSERT INTO spot ( latitude, longitude, user_id ) VALUES ( :lat, :long, :uid ) ";
//Update query
$query_params = array(
':lat' => $_POST['latitude'],
':long' => $_POST['longitude'],
':uid' => $_POST['user_id']
);
} else {
$query = "INSERT INTO spot ( latitude, longitude ) VALUES ( :lat, :long ) ";
//Update query
$query_params = array(
':lat' => $_POST['latitude'],
':long' => $_POST['longitude']
);
}
//execute query
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one:
$response["success"] = 0;
$response["message"] = "Database Error. Couldn't add lat/long-pair!";
die(json_encode($response));
}
$latt = $_POST['latitude'];
$longg = $_POST['longitude'];
$getId = "SELECT id FROM spot WHERE latitude=$latt AND longitude=$longg LIMIT 1";
//execute query
try {
$stmt2 = $db->prepare($getId);
$result2 = $stmt2->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one:
$response["success"] = 0;
$response["message"] = "Database Error. Couldn't retrieve like_id!";
die(json_encode($response));
}
$row = $stmt2->fetchAll();
if($row) {
$response["success"] = 1;
$response["message"] = "Spot Successfully Added!";
$response["like_id"] = $row[0]['id'];
echo json_encode($response);
}
} else {
?>
<h1>Registrer GPS-koordinater</h1>
<form action="idtest.php" method="post">
Latitude:<br />
<input type="text" name="latitude" value="" />
<br /><br />
Longitude:<br />
<input type="text" name="longitude" value="" />
<br /><br />
Google ID:<br />
<input type="text" name="user_id" value="" />
<br /><br />
<input type="submit" value="Opprett kolonne i 'spot'" />
</form>
<?php
}
?>
<?php
// TODO: Lag en sjekk for at lat/long faktisk er lat/long-verdier.
//load and connect to MySQL database stuff
require("config.inc.php");
if (!empty($_POST)) {
//initial query
if(isset($_POST['user_id']) && !empty($_POST['user_id'])) {
$query = "INSERT INTO spot ( latitude, longitude, user_id ) VALUES ( :lat, :long, :uid ) ";
//Update query
$query_params = array(
':lat' => $_POST['latitude'],
':long' => $_POST['longitude'],
':uid' => $_POST['user_id']
);
} else {
$query = "INSERT INTO spot ( latitude, longitude ) VALUES ( :lat, :long ) ";
//Update query
$query_params = array(
':lat' => $_POST['latitude'],
':long' => $_POST['longitude']
);
}
//execute query
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one:
$response["success"] = 0;
$response["message"] = "Database Error. Couldn't add lat/long-pair!";
die(json_encode($response));
}
$response["success"] = 1;
$response["message"] = "Spot Successfully Added!";
echo json_encode($response);
} else {
?>
<h1>Registrer GPS-koordinater</h1>
<form action="addspottest.php" method="post">
Latitude:<br />
<input type="text" name="latitude" value="" />
<br /><br />
Longitude:<br />
<input type="text" name="longitude" value="" />
<br /><br />
Google ID:<br />
<input type="text" name="user_id" value="" />
<br /><br />
<input type="submit" value="Opprett kolonne i 'spot'" />
</form>
<?php
}
?>