Php 关系SQL查询数组DB::table()->;选择()->;其中()->;get();[拉威尔]

Php 关系SQL查询数组DB::table()->;选择()->;其中()->;get();[拉威尔],php,mysql,laravel,Php,Mysql,Laravel,我在这段代码中遇到了一个错误,这个错误来自于'verification'更改它时,“小于”运算符是问题所在,它不会出现错误。如何重写此查询 $allRecords = DB::table('users')->select(DB::raw('CONCAT(name, " ", last_name) AS name'),'email as email_address')->where(array('verification'< 25,'is_admin'=>

我在这段代码中遇到了一个错误,这个错误来自于
'verification'<25
当我用
=>
更改它时,“小于”运算符是问题所在,它不会出现错误。如何重写此查询

$allRecords = DB::table('users')->select(DB::raw('CONCAT(name, " ", last_name) AS name'),'email as email_address')->where(array('verification'< 25,'is_admin'=>0,'is_approved'=>1))->orderby('id', 'DESC')->get();
$allRecords=DB::table('users')->select(DB::raw('CONCAT(name,“,last_name)AS name'),'email AS email address')->其中(array('verification'<25,'is_admin'=>0,'is_approved'=>1))->orderby('id','DESC')->get();
试试下面的方法

$allRecords = DB::table('users')
                 ->select(DB::raw('CONCAT(name, " ", last_name) AS name'),'email as email_address')
                 ->where('verification', '<', 25)
                 ->where(array('is_admin'=>0,'is_approved'=>1))
                 ->orderby('id', 'DESC')
                 ->get();
$allRecords=DB::table('users'))
->选择(DB::raw('CONCAT(name,“,last_name)作为name'),'email作为email地址')

->其中('verification','try this'verification)您的意思是“verificationjust”Verifications直到出现错误错误错误来自PHP或MySQL?