Php 如何从另一个模型的背面加载模型？

希望这能为我的问题增加一些背景。我有三种型号

我的构建模型：

public function buildComment(){
    return $this->hasMany('App\buildComment');
}
public function buildQuestion(){
    return $this->belongsTo('App\buildQuestion');
}

我的问题模型：

public function build(){
        return $this->hasMany('App\Build');
    }

buildComments模型：

public function build(){
    return $this->belongsTo('App\Build');
}

这是我的控制器：

public function viewQuestion(buildQuestion $buildQuestion){
    $builds = Build::with('buildComment')->get();

    return view('pages.questionView',compact('buildQuestion', 'builds'));
}

以下是我的看法：

@foreach($buildQuestion->build as $build)
       <ul class="list-group">
           <li class="list-group-item clearfix active">Build suggestion by: {{$build->user->name}}</li>
            <li class="list-group-item clearfix">Processor: <a href="/parts/cpu/{{$build->processor->id}}">{{$build->processor->name}}</a></li>
            <li class="list-group-item clearfix">Graphics Card: <a href="/parts/gpu/{{$build->videoCard->id}}">{{$build->videoCard->name}}</a></li>
            <li class="list-group-item clearfix">RAM: <a href="/parts/memory/{{$build->memory->id}}">{{$build->memory->name}}</a></li>
            <li class="list-group-item clearfix">Motherboard: <a href="/parts/motherboard/{{$build->motherboard->id}}">{{$build->motherboard->name}}</a></li>
            <li class="list-group-item clearfix">Power Supply: <a href="/parts/power-supply/{{$build->powerSupply->id}}">{{$build->powerSupply->name}}</a></li>
            <li class="list-group-item clearfix">Storage: <a href="/parts/storage/{{$build->storage->id}}">{{$build->storage->name}}</a></li>
            <li class="list-group-item clearfix">Optical Drive: <a href="/parts/optical-drive/{{$build->opticalDrive->id}}">{{$build->opticalDrive->name}}</a></li>
            <li class="list-group-item clearfix"><strong>Build Total Price: £{{$build->processor->price + $build->videoCard->price + $build->memory->price + $build->motherboard->price + $build->powerSupply->price + $build->storage->price + $build->opticalDrive->price}}</strong></li>
        </ul>
        @foreach($build->buildComment as $comment)
        {{$comment->body}}
        @endforeach
        <form action="/build-comment/post/{{$build->id}}" method="POST">
            <div class="form-group">
                <label for="body">Comment </label>
                <textarea class="form-control"  name="body"></textarea>
            </div>
            <input type="hidden" name="_token" value="{{ csrf_token() }}">
            <button type="submit" class="btn btn-primary">Submit</button>
        </form>
        @endforeach

@foreach（$buildQuestion->buildas$build）

构建建议人：{{{$Build->user->name}
处理器：
图形卡：
RAM:
主板：
电源：
存储：
光盘驱动器：
构建总价：{{$Build->processor->Price+$Build->videoCard->Price+$Build->memory->Price+$Build->主板->Price+$Build->powerSupply->Price+$Build->storage->Price+$Build->opticalDrive->Price}

@foreach（$build->buildComment作为$comment）
{{$comment->body}
@endforeach
评论
提交
@endforeach

我正在尝试获取属于生成的注释

buildQuestion有很多构建，构建有很多注释

---

如何表示这一点并检索构建的注释？

您可以通过嵌套加载在一个查询中获得所有注释

//one buildquestion with all the builds & comments
$buildQuestion = BuildQuestion::with('build.buildComment')->find(1); 

return view('pages.questionView',compact('buildQuestion'));

在你看来，筑巢是你的梦想

@foreach($buildQuestion->build as $build)
    //display stuff

    @foreach($build->buildComment as $comment)
         {{ $comment->body}}
    @endforeach
@endforeach

@foreach（$buildQuestion->buildas$build）

构建建议人：{{{$Build->user->name}
处理器：
图形卡：
RAM:
主板：
电源：
存储：
光盘驱动器：
构建总价：{{$Build->processor->Price+$Build->videoCard->Price+$Build->memory->Price+$Build->主板->Price+$Build->powerSupply->Price+$Build->storage->Price+$Build->opticalDrive->Price}

@foreach（$build->buildComment作为$comment）
{{$comment->body}
@endforeach
评论
提交
@endforeach

---

我在@EddyTheDove建议进行此更改后嵌套了另一个foreach，它成功了。

我想你想要的是

$buildQuestion->load（['builds'，'builds.comments'）谢谢，这看起来很有希望！但是我有单独的页面，每个页面都有问题。每个构建问题都会显示与其相关的构建，然后在构建下方显示注释。您的回答会导致所有注释显示在构建下方，无论是否与构建相关。我需要为相关版本显示注释。我认为这与find（）有关。然后尝试前面的查询，但保留double foreach。你必须循环所有的构建，循环所有的评论。很好，好人！如果你想看，我会更新的。
@foreach($buildQuestion->build as $build)
   <ul class="list-group">
       <li class="list-group-item clearfix active">Build suggestion by: {{$build->user->name}}</li>
        <li class="list-group-item clearfix">Processor: <a href="/parts/cpu/{{$build->processor->id}}">{{$build->processor->name}}</a></li>
        <li class="list-group-item clearfix">Graphics Card: <a href="/parts/gpu/{{$build->videoCard->id}}">{{$build->videoCard->name}}</a></li>
        <li class="list-group-item clearfix">RAM: <a href="/parts/memory/{{$build->memory->id}}">{{$build->memory->name}}</a></li>
        <li class="list-group-item clearfix">Motherboard: <a href="/parts/motherboard/{{$build->motherboard->id}}">{{$build->motherboard->name}}</a></li>
        <li class="list-group-item clearfix">Power Supply: <a href="/parts/power-supply/{{$build->powerSupply->id}}">{{$build->powerSupply->name}}</a></li>
        <li class="list-group-item clearfix">Storage: <a href="/parts/storage/{{$build->storage->id}}">{{$build->storage->name}}</a></li>
        <li class="list-group-item clearfix">Optical Drive: <a href="/parts/optical-drive/{{$build->opticalDrive->id}}">{{$build->opticalDrive->name}}</a></li>
        <li class="list-group-item clearfix"><strong>Build Total Price: £{{$build->processor->price + $build->videoCard->price + $build->memory->price + $build->motherboard->price + $build->powerSupply->price + $build->storage->price + $build->opticalDrive->price}}</strong></li>
    </ul>
    @foreach($build->buildComment as $comment)
    {{$comment->body}}
    @endforeach
    <form action="/build-comment/post/{{$build->id}}" method="POST">
        <div class="form-group">
            <label for="body">Comment </label>
            <textarea class="form-control"  name="body"></textarea>
        </div>
        <input type="hidden" name="_token" value="{{ csrf_token() }}">
        <button type="submit" class="btn btn-primary">Submit</button>
    </form>
    @endforeach