PHP，Jquery获取多数组，合并一行

概念： 在酒店中添加楼层、房间数和房间号并将其保存在db中

前端设计：

请看一下这张图片

我现在得到的是：

 "floor" => array:3 [▼
    0 => "3"
    1 => "2"
    2 => "1"
  ]
  "room_count" => array:3 [▼
    0 => "3"
    1 => "3"
    2 => "5"
  ]
  "room_number" => array:11 [▼
    0 => "101"
    1 => "102"
    2 => "103"
    3 => "201"
    4 => "202"
    5 => "203"
    6 => "101"
    7 => "102"
    8 => "103"
    9 => "104"
    10 => "105"
  ]

问题是:

如何循环获取：
三楼的房间号是101、102、103
二楼的房间号是201、202、203

---

楼层1的房间号为101、102、103、104、105

遍历每一层，计算房间数，然后通过房间号数组确定哪些房间号与该楼层相关联

考虑到您正在使用的阵列结构，诀窍是您需要有一个这样的循环，它可以通过按每层的房间数递增

$prev_index

来跟踪

$prev_index

---

您需要根据第一个数组中楼层的值设置房间编号数组索引，否则您就没有房间和楼层的轨迹。请尝试将

行编号

，作为

后缀

或

前缀

分配给前端每行输入的名称，然后提交，这样您就可以拥有轨迹。您的

房间号

数组索引应该具有楼层数组的值。因此，您可以根据楼层值区分房间编号。

<?php
$array = array(
    'floor' => array(
        0 => '3',
        1 => '2',
        2 => '1',
    ),
    'room_count' => array(
        0 => '3',
        1 => '3',
        2 => '5',
    ),
    'room_number' => array(
        0  => '101',
        1  => '102',
        2  => '103',
        3  => '201',
        4  => '202',
        5  => '203',
        6  => '101',
        7  => '102',
        8  => '103',
        9  => '104',
        10 => '105',
    ),
);
for ($prev_index = 0, $i = 0; $i < count($array['floor']); ++$i) {
    $floor        = $array['floor'][$i];
    $room_count   = $array['room_count'][$i];
    $room_numbers = array_slice($array['room_number'], $prev_index, $room_count);
    $prev_index   = $prev_index + $room_count;

    echo 'Floor '.$floor.' has '.$room_count.' rooms, with room numbers '.implode(', ', $room_numbers)."\n";
}

Floor 3 has 3 rooms, with room numbers 101, 102, 103
Floor 2 has 3 rooms, with room numbers 201, 202, 203
Floor 1 has 5 rooms, with room numbers 101, 102, 103, 104, 105