如何使用php从mysql数据库中获取所有匹配的记录?
我在mysql数据库中设置了下表如何使用php从mysql数据库中获取所有匹配的记录?,php,mysql,Php,Mysql,我在mysql数据库中设置了下表 mem_id | pid | content 0 | 1 | All the content is here 0 | 2 | All the content is here 0 | 3 | All the content is here 现在的问题是获取所有匹配的mem\u id值,并将其存储在php中的数组中 示例:名为$id的变量具有值0 因此,现在我必须获取列内容下的所有值,但只获取与用户的mem\u id匹配的
mem_id | pid | content
0 | 1 | All the content is here
0 | 2 | All the content is here
0 | 3 | All the content is here
现在的问题是获取所有匹配的mem\u id
值,并将其存储在php中的数组中
示例:名为$id
的变量具有值0
因此,现在我必须获取列内容下的所有值,但只获取与用户的mem\u id
匹配的值
有人能帮我吗,我需要用php和mysql查询来获取所有的值
我当前的代码:
$con=mysqli_connect("localhost","*****","******","*****");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM user_friends WHERE mem_id = '$_SESSION[SESS_MEMBER_ID]' LIMIT 1");
while($row = mysqli_fetch_array($result))
{
$friends = $row['fid'];
}
使用PHP可以像这样查询:
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$id = intval($id); // Put your ID here
$query = "SELECT * FROM yourTABLE WHERE mem_id=$id";
if ($result = mysqli_query($link, $query)) {
while ($row = mysqli_fetch_assoc($result)) {
print_r($row);
}
mysqli_free_result($result);
}
?>
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$id = intval($id); // Put your ID here
$query = "SELECT * FROM yourTABLE WHERE mem_id=$id";
if ($result = mysqli_query($link, $query)) {
while ($row = mysqli_fetch_assoc($result)) {
print_r($row);
}
mysqli_free_result($result);
}
?>
$query="select * from TABLE_NAME where `mem_id`='$id'";