Php 在这里,我需要将数据提交到数据库,并使用ajax获取要查看的id

Php 在这里,我需要将数据提交到数据库,并使用ajax获取要查看的id,php,jquery,ajax,Php,Jquery,Ajax,以下是我的观点 <html> <body> <form method="post" name="myForm1" id="myForm1" enctype="multipart/form-data" > Email: <input type="text" name="email" id="email"> Question: <input type="text" name="qText" id="qText">

以下是我的观点

<html>
<body>
    <form method="post" name="myForm1" id="myForm1" enctype="multipart/form-data" >
    Email: <input type="text" name="email" id="email">
    Question: <input type="text" name="qText" id="qText">
    <input id="submitbutton" type="submit">
    </form>
  <div id="abc"></div>
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
    <script>   //no need to specify the language
       $(document).ready(function() {

       $('#myForm1').on("submit",function(e) {

            //var form = $(this);
            //dataString = $("#myForm1").serialize();
            e.preventDefault();

            $.ajax({
                type: "POST",
                url: "<?php echo site_url('form_controller/insert_into_db'); ?>",
                data: $(this).serialize(),
                //dataType: "json",
                success: function(data){
                   // top.location.href = "<?php echo site_url('form_controller/callform'); ?>";
                    //$.each(data.results, function(){
                   // $("#abc").append('<div><b>' + id.id + '</b></div><hr />');

                    //});
                    /*var site_url = "<?php// echo site_url('form_controller/callform/') ?>";
                    site_url = site_url +"/" + id;
                    $("#abc").load(site_url);*/
                    <?php //foreach(): ?>

                    var site_url = "<?php echo site_url('form_controller/callform'); ?>";
                    var mydata=window.JSON.stringify(data.trim());
                    alert(mydata);
                    //site_url = site_url +"/" +data.id;
                    alert(site_url);
                    $("#abc").load(site_url);
                    //$('#abc').html(data);
                    var item = data;
                    alert(item.id);

                }//,
                //error: function() { alert("Error posting feed."); }
           });

        });
        });
    </script>   
</body>
</html>
型号

 <?php

 class Form_model extends CI_Model{

function insertQ(){
    $email = $this->input->post('email');
    $text = $this->input->post('qText');
    $this->db->query("insert into form (email,text) values('$email','$text')");
    $this->load->database();
    $query = $this->db->query("SELECT MAX(id) AS id FROM form");
    return $query->result();

 }
 }

您可以获取插入的id

    $id = $this->db->insert_id();
    $id = $this->db->insert_id();