Php 如何为返回空结果的现有单行输出查询

我有一个页面显示一篇文章的全部细节。但这是一个错误

试图获取非对象的属性“title”（视图：C:\xampp\htdocs\myapp\resources\views\public area\View.blade.php） https://localhost/myapp/public/post/the-duchess-took-her-choice-and-was-going-to-begi/7

在blade中显示MySQL结果之前，一切似乎都很正常

这是我的密码： 逻辑：

WEB.PHP：

Route::get('/post/{postTitle?}/{postId}', [PublicController::class, 'postView3'])->name('postView3')->where(['post-title' => '[A-Za-z]+', 'post-id' => '[0-9]+']);

公共控制员：

namespace App\Http\Controllers;
use App\Http\Controllers\Controller;
use Illuminate\Support\Str;
class PublicController extends Controller
{
    /**
     * Show a user listing page.
     * @return \Illuminate\Contracts\Support\Renderable
     */
    public function postView3($postId)
    {
        ...
        //Fetch required classified-ad posts
        $posts = (new \App\Logic\Listings\PostData)->singlePost_full_data3($postId);

        /* Display page */
        return view('public-area.view', [
            ..., 'posts'=>$posts
        ]);
    }

VIEW.BLADE.PHP

<?php 
$pageTitle = $posts->title; ?>
@extends('templates.template-public')
@section('page_title') {{$pageTitle}} @endsection
@section('main_content')

...
                <h1>{{$pageTitle}} Listings</h1>
...

<?php
dd($posts); 
$pageTitle = $posts->title; ?>
@extends('templates.template-public')
@section('page_title') {{$pageTitle}} @endsection
@section('main_content')
...

<?php
dd($posts); 
$pageTitle = $posts->title; ?>
@extends('templates.template-public')
@section('page_title') {{$pageTitle}} @endsection
@section('main_content')
...

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