动态生成的按钮PHP不工作

所以我在php上用循环动态创建了一些按钮 看起来像这样

while($row = mysql_fetch_array($sql))
{
    $id = $row["DeviceID"];
    $name = $row["Name"];
    $description = $row["Description"];
    $location = $row["Location"];
    $image = $row["image"];
    $dynamicList .= '<div class="section"> 
                         <div class="container"> 
                             <div class="row"> 
                                 <div class="col-md-6"> 
                                     <img src="'.$image.'" class="img-responsive"> 
                                 </div>
                                 <div class="col-md-4"> 
                                     <h1 class="text-success">The Light is ON</h1> 
                                     <h3>'.$_SESSION['Username'].'s '.$name.' ('.$location.')</h3> 
                                     <p>Light Location: '.$location.'<br>Light Description: '.$description.'<br><br><br><br><br>Intelligent Hours<br><br>Weekdays<br>7:00am - 7:45am&nbsp;<br>5:45pm - 7:30pm<br>8:30pm - 11:30pm<br><br>Weekends<br>TBD&nbsp;</p>
                                 </div>
                                 <div class="col-md-2">
                                     <button type="submit" name="login" id="login" class="btn btn-default">Login</button>
                                     <!--<button type="submit" name="button" id="button'.$id.'" value="'.$id.'" class="btn btn-default">Toggle Off</button>-->
                                 </div>
                             </div>
                         </div>
                     </div>';
}

<?php
if(isset($_REQUEST['login']))
{
    echo "<script type='text/javascript'>alert('button with Value = '.$value.'')</script>";
}

while（$row=mysql\u fetch\u数组（$sql））
{
$id=$row[“设备id”]；
$name=$row[“name”]；
$description=$row[“description”]；
$location=$row[“location”]；
$image=$row[“image”]；
$dynamicList='
灯亮着
“.$”会话['Username'].'s'.$name.（“.$location.”）
灯光位置：“.$Location.”
灯光描述：“.$Description.”




智能时间

工作日
上午7:00-7:45
下午5:45-7:30
晚上8:30-11:30
周末
待定

登录
';
}

当我试图在用户触发它时捕获它时，它不起作用

我像这样捕捉它

while($row = mysql_fetch_array($sql))
{
    $id = $row["DeviceID"];
    $name = $row["Name"];
    $description = $row["Description"];
    $location = $row["Location"];
    $image = $row["image"];
    $dynamicList .= '<div class="section"> 
                         <div class="container"> 
                             <div class="row"> 
                                 <div class="col-md-6"> 
                                     <img src="'.$image.'" class="img-responsive"> 
                                 </div>
                                 <div class="col-md-4"> 
                                     <h1 class="text-success">The Light is ON</h1> 
                                     <h3>'.$_SESSION['Username'].'s '.$name.' ('.$location.')</h3> 
                                     <p>Light Location: '.$location.'<br>Light Description: '.$description.'<br><br><br><br><br>Intelligent Hours<br><br>Weekdays<br>7:00am - 7:45am&nbsp;<br>5:45pm - 7:30pm<br>8:30pm - 11:30pm<br><br>Weekends<br>TBD&nbsp;</p>
                                 </div>
                                 <div class="col-md-2">
                                     <button type="submit" name="login" id="login" class="btn btn-default">Login</button>
                                     <!--<button type="submit" name="button" id="button'.$id.'" value="'.$id.'" class="btn btn-default">Toggle Off</button>-->
                                 </div>
                             </div>
                         </div>
                     </div>';
}

<?php
if(isset($_REQUEST['login']))
{
    echo "<script type='text/javascript'>alert('button with Value = '.$value.'')</script>";
}

---

啊，我意识到我没有放表单标签。我试试看是否有效again@A.Wolffatm我没有任何特定的“预期行为”，我只是在瞎弄弄弄按钮来解决NVM问题谢谢Norlihazmey，很抱歉浪费了你的时间