如何使用GET从php中的select选项检索数据
嗨,我的代码有点问题。我需要从选择选项中检索数据,该选项是从sql中选择的。代码如下:如何使用GET从php中的select选项检索数据,php,get,echo,option,Php,Get,Echo,Option,嗨,我的代码有点问题。我需要从选择选项中检索数据,该选项是从sql中选择的。代码如下: <form action="zadany.php" method="get"> <label for="select"> Komu zadat novej úkol: <select name="users"> <?php $sql = "SELECT * FROM users"; $result = mysql_query($sql) or
<form action="zadany.php" method="get">
<label for="select">
Komu zadat novej úkol:
<select name="users">
<?php
$sql = "SELECT * FROM users";
$result = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($result))
{
$id=$row["id"];
$username=$row["username"];
$options.="<OPTION VALUE=\"$id\">".$username;
}
?>
<option>
<? echo $options ?>
</option>
</select>
<br />
Typ úkolu:
<table border="1">
<input type="radio" name="ukol" value="bla1">Ukol 1</input>
<input type="radio" name="ukol" value="bla2">Ukol 2</input>
<input type="radio" name="ukol" value="bla3">Ukol 3</input>
</table>
<br />
<input type="submit" value="zadej úkol">
</form>
novejúkol:
Typúkolu:
Ukol 1
Ukol 2
Ukol 3
行动是:
<?php
include 'core/init.php';
protect_page();
include 'includes/overall/header.php';
echo $_GET['users'];
switch ($_GET["ukol"]) {
case "bla1":
echo 'ukol 1';
break;
case "bla2";
echo 'ukol 2';
break;
case "bla3":
echo 'ukol 3';
break;
default:
echo 'nezadany ziadny ukol';
}
include 'includes/overall/footer.php';
?>
例如,我需要回显选择菜单中的所选选项。有人能帮我解决这个问题吗?非常感谢您的每一篇帖子和回复 您的PHP代码正在生成以下代码:
<option>
<OPTION value="your id #1"> Username
</option>
用户名
你能试一下吗
<select name="users">
<?php
$sql = "SELECT * FROM users";
$result = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($result))
{
$id=$row["id"];
$username=$row["username"];
$options.="<OPTION VALUE=\"$id\">".$username."</OPTION>";
}
?>
<? echo $options ?>
</select>