Php 使用codeigniter连接表并将数据提取到表中

我有两个db表，分别命名为

verification\u details

和

verification\u questions

<代码>验证id在两个表中很常见。在

verification\u details

表中，有一个

user\u id

字段，基于此

user\u id

字段，一个或多个验证详细信息插入到

验证详细信息

表中，并基于

验证id

一个或多个验证问题插入到

验证问题

表中。 我在模型中使用此代码进行连接查询

function get_records() {

    $this->db->select("a.criteria_question,a.criteria_answer,a.validation_statement");
        $this->db->from("verification_questions as a");
        $this->db->join('verification_details as b', 'a.verification_id = b.verification_id');
        $query = $this->db->get();
        return $query->result();    
}

---

我想要控制器代码，用于从两个表中获取所有数据并将其显示在表中。

您可以在模型中创建结果数组并在控制器中使用它

型号：

function get_records()
{
        $this->db->select("a.criteria_question,a.criteria_answer,a.validation_statement");
        $this->db->from("verification_questions as a");
        $this->db->join('verification_details as b', 'a.verification_id = b.verification_id');
        $query = $this->db->get();
        $select = array();
        foreach ($query->result() as $row) {
            $select[] = $row;
        }
        if (count($select) > 0)
            return $select;
        return NULL;
}

$data['result']=$this->modelname->get_records();
$this->load->view('your_view', $data);

<table><tr><td>Question></td></tr>
    if(count($result)>0){
        foreach($result as $row){ ?>
            <tr><td><?= $row->criteria_question; ?></td></tr>
        <?php}
    } ?>
</table>

您可以在控制器中使用此函数来获取结果数组

控制器：

function get_records()
{
        $this->db->select("a.criteria_question,a.criteria_answer,a.validation_statement");
        $this->db->from("verification_questions as a");
        $this->db->join('verification_details as b', 'a.verification_id = b.verification_id');
        $query = $this->db->get();
        $select = array();
        foreach ($query->result() as $row) {
            $select[] = $row;
        }
        if (count($select) > 0)
            return $select;
        return NULL;
}

$data['result']=$this->modelname->get_records();
$this->load->view('your_view', $data);

<table><tr><td>Question></td></tr>
    if(count($result)>0){
        foreach($result as $row){ ?>
            <tr><td><?= $row->criteria_question; ?></td></tr>
        <?php}
    } ?>
</table>

最后，您必须将结果变量传递给视图，以便在表中显示

查看：

function get_records()
{
        $this->db->select("a.criteria_question,a.criteria_answer,a.validation_statement");
        $this->db->from("verification_questions as a");
        $this->db->join('verification_details as b', 'a.verification_id = b.verification_id');
        $query = $this->db->get();
        $select = array();
        foreach ($query->result() as $row) {
            $select[] = $row;
        }
        if (count($select) > 0)
            return $select;
        return NULL;
}

$data['result']=$this->modelname->get_records();
$this->load->view('your_view', $data);

<table><tr><td>Question></td></tr>
    if(count($result)>0){
        foreach($result as $row){ ?>
            <tr><td><?= $row->criteria_question; ?></td></tr>
        <?php}
    } ?>
</table>

问题>
如果（计数（$result）>0）{
foreach（$result作为$row）{？>

在模型中

function get_records() {

    $this->db->select("a.criteria_question,a.criteria_answer,a.validation_statement");
    $this->db->from("verification_questions as a");
    $this->db->join('verification_details as b', 'a.verification_id = b.verification_id');
    $query = $this->db->get();
    $result = $query->result_array();
    return $result;
}

内控

$data['table'] = $this->Model_name->get_records();
$this->load->view('view_name',$data);

以及

<table>
    <tr>
        <th>Question</th>
        <th>Answer</th>
        <th>Validation</th>
    </tr>
    <?php
        foreach ( $table as $new_item )
        {
            ?>
            <tr>
                <td><?php echo $new_item['table field1']?></td>
                <td><?php echo $new_item['table field2']?></td>
                <td><?php echo $new_item['table field3']?></td>
            </tr>
        <?php
        }

    ?>
</table>

问题:
答复
验证

您的代码几乎正确。但是您让它变得有点长，我的意思是不需要使用foreach循环两次，您也可以使用一次来实现它！！！但是我感谢您的指导！！