Php 如何使用唯一键和重复数据合并不同长度的数组

更新：一个数组是实际数组，另一个是对象数组

我想在键匹配的地方合并两个重复数据的数组

$arr1 = array(
  object(stdClass){"id" => 1, "key" => 1, "content" => "blah", "extra" => "extra data"},
  object(stdClass){"id" => 2, "key" => 2, "content" => "bleep", "extra" => "extra data"},
  object(stdClass){"id" => 3, "key" => 3, "content" => "bloop", "extra" => "extra data"},
  object(stdClass){"id" => 4, "key" => 2, "content" => "zip", "extra" => "extra data"},
  object(stdClass){"id" => 5, "key" => 1, "content" => "zorp", "extra" => "extra data"}
);

$arr2 = array(
  array("id" => 1, "otherkey" => 1, "title" => "foo"),
  array("id" => 2, "otherkey" => 2, "title" => "bar"),
  array("id" => 3, "otherkey" => 3, "title" => "baz")
);

$desiredArr = {
  array("id" => 1, "key" => 1, "content" => "blah", "extra" => "extra data", "title" => "foo"),
  array("id" => 2, "key" => 2, "content" => "bleep", "extra" => "extra data", "title" => "bar"),
  array("id" => 3, "key" => 3, "content" => "bloop", "extra" => "extra data", "title" => "baz"),
  array("id" => 4, "key" => 2, "content" => "zip", "extra" => "extra data", "title" => "bar"),
  array("id" => 5, "key" => 1, "content" => "zorp", "extra" => "extra data", "title" => "foo")
};

我已经尝试了嵌套的

foreach（）

的

array\u merge（）、array\u walk\u recursive（）、array\u combine（）、array\u push（）

，并且仍在努力实现这两种方法的成功组合，但我得到的最接近的结果是将

$arr2

附加到

$arr1

，结果是：

$newArr = {
  array("id" => 1, "key" => 1, "content" => "blah", "extra" => "extra data"),
  array("id" => 2, "key" => 2, "content" => "bleep", "extra" => "extra data"),
  array("id" => 3, "key" => 3, "content" => "bloop", "extra" => "extra data"),
  array("id" => 4, "key" => 2, "content" => "zip", "extra" => "extra data"),
  array("id" => 5, "key" => 1, "content" => "zorp", "extra" => "extra data"),
  array("id" => 6, "otherkey" => 1, "title" => "foo"),
  array("id" => 7, "otherkey" => 2, "title" => "bar"),
  array("id" => 8, "otherkey" => 3, "title" => "baz")
};

---

如果有人在你的指导下遇到这种情况，我们将不胜感激

您可以使用

map

重复

$arr1

使用

array\u search

和

array\u column

搜索

$arr2

$arr1 = array(
  (object)array("id" => 1, "key" => 1, "content" => "blah", "extra" => "extra data"),
  (object)array("id" => 2, "key" => 2, "content" => "bleep", "extra" => "extra data"),
  (object)array("id" => 3, "key" => 3, "content" => "bloop", "extra" => "extra data"),
  (object)array("id" => 4, "key" => 2, "content" => "zip", "extra" => "extra data"),
  (object)array("id" => 5, "key" => 1, "content" => "zorp", "extra" => "extra data")
);

$arr2 = array(
  array("id" => 1, "otherkey" => 1, "title" => "foo"),
  array("id" => 2, "otherkey" => 2, "title" => "bar"),
  array("id" => 3, "otherkey" => 3, "title" => "baz")
);

$desiredArr = array_map(function($v) use($arr2) {
    $v = (array)$v;
    $key = array_search($v["id"], array_column($arr2, 'id'));
    $v["title"] = $arr2[$key]["title"];
    return $v;
}, $arr1);

echo "<pre>";
print_r( $desiredArr );
echo "</pre>";

---

这是无效的PHP…您期望的结果是什么？@prasannaputtaswamy我想要$desiredar的结果（我正在编辑排版）这些数组无效format@prasannaputtaswamy问题已更新，以更正格式并使我正在使用的密钥更清晰我已更新问题，以更正数组并将id交换为密钥，使其更清晰。我不认为这会影响你的回答，但我尝试的时候会得到500分。现在正在处理它。@bardicwarrior更新后的数组仍然不是有效数组。@bardicwarrior但我想我知道你的意思。请检查我的最新答案。我很抱歉-我认为当所有阵列以这种最小格式排列时，更容易看到问题-我感谢您继续！这对我很有用，我以前从未使用过array_列，也没有使用过array_搜索-感谢您向我介绍这些工具@巴第克勇士很乐意帮忙：）

Array
(
    [0] => Array
        (
            [id] => 1
            [key] => 1
            [content] => blah
            [extra] => extra data
            [title] => foo
        )

    [1] => Array
        (
            [id] => 2
            [key] => 2
            [content] => bleep
            [extra] => extra data
            [title] => bar
        )

    [2] => Array
        (
            [id] => 3
            [key] => 3
            [content] => bloop
            [extra] => extra data
            [title] => baz
        )

    [3] => Array
        (
            [id] => 4
            [key] => 2
            [content] => zip
            [extra] => extra data
            [title] => foo
        )

    [4] => Array
        (
            [id] => 5
            [key] => 1
            [content] => zorp
            [extra] => extra data
            [title] => foo
        )

)