Php 检查数组是否包含其他数组的所有元素?
我有2个数组,第二个数组必须包含第一个数组中的所有元素,如何检查?多谢各位Php 检查数组是否包含其他数组的所有元素?,php,Php,我有2个数组,第二个数组必须包含第一个数组中的所有元素,如何检查?多谢各位 For example array 1: Array ( [0] => Email [1] => 1_Name ) array 2: Array ( [0] => 1_Name [1] => ) In this case it is invalid , as array 2 do not have Email array 1: Array ( [0] => Email [1] =&
For example
array 1: Array ( [0] => Email [1] => 1_Name )
array 2: Array ( [0] => 1_Name [1] => )
In this case it is invalid , as array 2 do not have Email
array 1: Array ( [0] => Email [1] => 1_Name )
array 2: Array ( [0] => 1_Name [1] => Address [2]=> Email )
In this case it is valid
使用并测试其输出长度是否相同:
if (count(array_intersect($arr1, $arr2)) === count($arr1)) {
// contains all
}
对于键也必须匹配的关联数组,请改用。在此处可能很有用
if( array_diff($array1,$array2)) {
// array1 contains elements that are not in array2
echo "invalid";
}
else {
// all elements of array1 are in array2
echo "valid";
}
有一个
array\u intersect()
像@Michael建议的那样。如果您想知道缺少哪个元素,可以使用array_diff()
您不应该对$arr2进行计数吗?@stackoverownewbie实际上并不重要。关键是两者的交点与第一个或第二个的内容相同,因此包含相同的集合。
if( array_diff($array1,$array2)) {
// array1 contains elements that are not in array2
echo "invalid";
}
else {
// all elements of array1 are in array2
echo "valid";
}