php变量不存储

我正在尝试用php创建一个db类，它将主机ect作为变量。我无法使初始化值保持不变，我不确定原因。当我在顶部将它们设置为public时，它工作得很好，但是当我尝试在构造函数中初始化它们时，它不工作

    class Database {

    public $dbHost;
    public $dbUser;
    public $dbPass;
    public $dbName;

    public $db;

    public function __construct($Host, $User, $Pass, $Name){ 
        $dbHost = $Host;
        $dbUser = $User;
        $dbPass = $Pass;
        $dbName = $Name;
        $this->dbConnect();
    }

    public function dbConnect(){
        echo $dbPass;
        $this->db = new mysqli($this->dbHost, $this->dbUser, $this->dbPass, $this->dbName);

        /* check connection */
        if (mysqli_connect_errno()){
            printf("Connect failed: %s\n", mysqli_connect_error());
            exit();
        }else{
            //echo 'connection made';
        }
    }

---

您没有在构造函数中正确初始化它们；尝试：

$this->dbHost = $Host;

---

您当前正在初始化一个名为$dbHost的局部变量，其作用域只是构造函数本身。

您必须使用

$this

来访问类内的实例变量，例如

$this->dbHost=$Host
更改此项：

public function __construct($Host, $User, $Pass, $Name){ 
        $dbHost = $Host;
        $dbUser = $User;
        $dbPass = $Pass;
        $dbName = $Name;
        $this->dbConnect();
    }

为此：

public function __construct($Host, $User, $Pass, $Name){ 
        $this->dbHost = $Host;
        $this->dbUser = $User;
        $this->dbPass = $Pass;
        $this->dbName = $Name;
        $this->dbConnect();
    }

public function __construct($Host, $User, $Pass, $Name){ 
        $this->dbHost = $Host;
        $this->dbUser = $User;
        $this->dbPass = $Pass;
        $this->dbName = $Name;
        $this->dbConnect();
    }

使用这个->

public function __construct($Host, $User, $Pass, $Name){ 
    $this->dbHost = $Host;
    $this->dbUser = $User;
    $this->dbPass = $Pass;
    $this->dbName = $Name;
    $this->dbConnect();
}

试试这个：