PHP-如何从查询中获取订单并获取；地点编号“；

我如何从表中选择前40名数据（基于

金额

），然后找到特定用户在该数据组中的位置

例如，我选择了前40个数据：

if($userdata['forum_moderator'] == 1){
$c = $dbh->prepare("SELECT * FROM referral_competition ORDER BY amount DESC LIMIT 5");
$c->execute();

$competition = $c->fetchAll();

    echo "<pre>";
    var_dump($competition);
    echo "</pre>";

如何根据用户id找出特定用户在上面的数组中的位置

例如：

---

您被放置在第3位，并且您在内部有

amount:8

选择获取前40名并向其添加排名列。另一个select仅获取特定用户的排名和金额

  $ordered = [];
  foreach($competition as $k=>$result) {
    $rank = $k + 1; //Add plus one as the indexed resultset starts from zero
    $user_id = $result['userid']; //Grab the user id
    $ordered[$user_id]=$result; //Little trick to add the user id as the array index key
    $ordered[$user_id]['rank']=$rank; //Add the rank as new array element
  }

  //Now you can get any user record out of the array by using the userid as key

  //Example:
  $user = $ordered[3];
  $rank = $user['rank'];

---

此解决方案不需要您更改已有的sql查询。它还使您能够快速访问用户数据

---

谢谢，现在当我执行var_dump（）时，它会显示正确的“顺序”。不过，当我试着回应时：什么也没显示。对不起，我帮不了你。这似乎是一个PHP问题，我不是这方面的专家。为什么不简单地使用$competition的数组键并添加1？您所说的“添加1”是什么意思？你能举个例子吗？用户名为4的用户是$competition[2]的元素，因此她将数字2+1=3…@VMai，但我该怎么做呢？比如：$compatitions[$userid]+1？我不知道你用这个数组做什么，所以我不能说。juergen d解决方案的好处是秩包含在数组元素中，而不依赖于数组本身。处理此数组的部分不知何故丢失了。

select amount, rank 
from 
(
  SELECT *, @rank := @rank + 1 as rank
  FROM referral_competition 
  CROSS JOIN (select @rank := 0) r
  ORDER BY amount DESC 
  LIMIT 40
) tmp
where userid = $someUser

  $ordered = [];
  foreach($competition as $k=>$result) {
    $rank = $k + 1; //Add plus one as the indexed resultset starts from zero
    $user_id = $result['userid']; //Grab the user id
    $ordered[$user_id]=$result; //Little trick to add the user id as the array index key
    $ordered[$user_id]['rank']=$rank; //Add the rank as new array element
  }

  //Now you can get any user record out of the array by using the userid as key

  //Example:
  $user = $ordered[3];
  $rank = $user['rank'];