Php 无法向服务器发送GET/POST请求

我正在尝试向服务器发送get数据并读取服务器消息作为响应。后端是PHP，工作正常。但是，每当我试图从android发送数据时，

$\u GET

或

$\u POST

或

$\u RESPONSE

数组都保持为空

背景是：

 @Override
        protected Void doInBackground(Void... params) {
            Log.d(TAG,"Inside do in background");

            try {

                Log.d(TAG,"Here is new url.");
                URL url = new URL("http://192.168.1.33/post/home.php");

                HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();


                urlConnection.setRequestMethod("GET");
                urlConnection.setDoInput(true);
                urlConnection.setDoOutput(true);
                urlConnection.setRequestProperty("Content-Type", "application/json");


//sending data in json format

                JSONObject jsonObject = new JSONObject();

                jsonObject.put("name","salman Khan");

                jsonObject.put("password","khankhan");

                String sendingString ;

                sendingString = jsonObject.toString();

                byte[] outputBytes = sendingString.getBytes("UTF-8");

                Log.d(TAG, "Output bytes are " + sendingString);

                OutputStream outputStream = urlConnection.getOutputStream();

                Log.d(TAG," got output stream.");
                outputStream.write(outputBytes);

                Log.d(TAG,"I am waiting for response code");
                int responseCode = urlConnection.getResponseCode();

                Log.d(TAG,"response code: " + responseCode);

                if ( responseCode == HttpURLConnection.HTTP_OK)
                {
                    BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));

                    String line;

                    Log.d(TAG,"Before reading the line.");

                    while ( (line = bufferedReader.readLine()) != null )
                    {
                        Log.d(TAG, " The line read is: " + line);
                    }
                }
            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            } catch (JSONException e) {
                e.printStackTrace();
            }
            return null;
        }

PHP代码：

<?php

        $response = array();
        // print_r($_GET);
        print_r($_REQUEST);
        if ( !empty($_GET['name']) || !empty($_GET['password']))
        {
                // echo "I am in true.";
                $response['name'] = $_GET['name'];
                $response['password'] = $_GET['password'];
                $response['status'] = true;
        }
        else
        {
                $response['status'] = false;
        }
        echo json_encode($response);
 ?>

---

检查manifes文件中添加的以下权限

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"/>

---

使用截击，这是传输数据的最佳方式

http://developer.android.com/intl/es/training/volley/index.html

---

在您的请求类（扩展请求）中，重写getParams（）方法。您也可以对标题执行同样的操作，只需覆盖getHeaders（）。

如果您是通过JSON而不是post字段发送数据，则数据将不在$\u post中。你必须从stdin中读取它。基本上我想发送$\u POST数组。同样的，请指导我。我不懂安卓，所以我不能指导你。但我可以告诉您，看起来您正在以application/json的形式发送数据。如果是这种情况，那么您需要在PHP中正确读取数据，或者以不同的方式发送数据。我已经添加了它。应用程序正在与服务器通信。

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"/>