Php prod环境中异常消息的FOSRestBundle配置
我正在努力解决与FOSRestBundle(版本0.13.*)相关的问题 我有一些RESTAPI抛出一些异常,我想没有什么异常。但是,尽管我做了特定的配置,允许在响应中格式化异常消息,即使在生产中也是如此(遵循我在这里找到的文档:),JSON响应仍然是空的 示例如下:Php prod环境中异常消息的FOSRestBundle配置,php,symfony,fosrestbundle,Php,Symfony,Fosrestbundle,我正在努力解决与FOSRestBundle(版本0.13.*)相关的问题 我有一些RESTAPI抛出一些异常,我想没有什么异常。但是,尽管我做了特定的配置,允许在响应中格式化异常消息,即使在生产中也是如此(遵循我在这里找到的文档:),JSON响应仍然是空的 示例如下: http://host/app_dev.php/api/postcode/search?postcode= 结果: HTTP 400: {"status":"error","status_code":400,"status_
http://host/app_dev.php/api/postcode/search?postcode=
结果:
HTTP 400: {"status":"error","status_code":400,"status_text":"Bad Request","current_content":"","message":"You must provide a postcode"}
HTTP 400: []
但是
结果:
HTTP 400: {"status":"error","status_code":400,"status_text":"Bad Request","current_content":"","message":"You must provide a postcode"}
HTTP 400: []
我的API控制器如下所示:
/**
* Search post codes
*
* @param Request $request Request
* @param Promotion $promotion Promotion
*
* @Rest\View()
*
* @throws BadRequestHttpException
* @return array
*/
public function searchAction(Request $request, Promotion $promotion)
{
// Get post code
$postCode = $request->query->get('postcode');
if (!$postCode) {
throw new BadRequestHttpException('You must provide a postcode');
}
// SOME LOGIC HERE TO GET DATA
return $data;
}
fos_rest:
routing_loader:
default_format: json
view:
mime_types:
json: ['application/json; charset=UTF-8']
formats:
json: true
view_response_listener: force
format_listener: false
access_denied_listener:
json: true
body_listener: true
exception:
messages:
Symfony\Component\HttpKernel\Exception\BadRequestHttpException: true
fos_rest配置如下所示:
/**
* Search post codes
*
* @param Request $request Request
* @param Promotion $promotion Promotion
*
* @Rest\View()
*
* @throws BadRequestHttpException
* @return array
*/
public function searchAction(Request $request, Promotion $promotion)
{
// Get post code
$postCode = $request->query->get('postcode');
if (!$postCode) {
throw new BadRequestHttpException('You must provide a postcode');
}
// SOME LOGIC HERE TO GET DATA
return $data;
}
fos_rest:
routing_loader:
default_format: json
view:
mime_types:
json: ['application/json; charset=UTF-8']
formats:
json: true
view_response_listener: force
format_listener: false
access_denied_listener:
json: true
body_listener: true
exception:
messages:
Symfony\Component\HttpKernel\Exception\BadRequestHttpException: true
据我所知,fos_rest.exception.messages配置数组应该列出我希望在生产中序列化错误消息的异常。正如您在控制器的代码中所看到的,此响应包含将显示给客户端的已翻译错误消息。为什么忽略此配置?
我可以肯定地说,即使在prod环境中,配置也已正确加载,因为如果我在conf中错误地说出类名,它将失败,并出现“无法加载类”异常
我错过了什么?提前感谢您给我的任何提示…我还没有尝试过,但您似乎忘记了这句话:
exception:
codes:
'Symfony\Component\Routing\Exception\ResourceNotFoundException': 404
试试看
你有没有提到:
twig:
...
...
exception_controller: 'FOS\RestBundle\Controller\ExceptionController::showAction'
我有一个类似的问题,你的问题实际上帮我解决了! 我知道已经晚了,但我发现清除
prod
缓存有助于我解决这个问题
此外,以下是我的设置:
fos_rest:
param_fetcher_listener: true
body_listener:
array_normalizer: fos_rest.normalizer.camel_keys
format_listener: true
view:
view_response_listener: 'force'
formats:
json: true
templating_formats:
html: true
force_redirects:
html: true
failed_validation: HTTP_BAD_REQUEST
default_engine: twig
routing_loader:
default_format: json
serializer:
serialize_null: true
access_denied_listener:
json: true
exception:
enabled: true
messages:
Symfony\Component\HttpKernel\Exception\BadRequestHttpException: true
我还想知道,除非您使用HttpException,否则您是否必须始终将异常显式地添加到配置的code
和messages
部分:
throw new HttpException(400, "New comment is not valid.");
谢谢大家!<代码>例外。消息正是我要找的。您好,如果您将我的答案标记为正确与否,我将不胜感激:D谢谢