Php 如何在cURL POST请求中使用数组

我想知道如何使这段代码支持数组？此时，

images

数组似乎只发送第一个值

这是我的密码：

<?php
//extract data from the post
extract($_POST);

//set POST variables
$url = 'http://api.example.com/api';
$fields = array(
            'username' => "annonymous",
            'api_key' => urlencode("1234"),
            'images[]' => urlencode(base64_encode('image1')),
            'images[]' => urlencode(base64_encode('image2'))
        );

//url-ify the data for the POST
foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; }
rtrim($fields_string, '&');

//open connection
$ch = curl_init();

//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);

//execute post
$result = curl_exec($ch);
echo $result;

//close connection
curl_close($ch);
?>

---

images[]

中的第二个值发生了什么变化？

您只是错误地创建了数组。您可以使用：

因此，您可以使用的整个代码是：

<?php
//extract data from the post
extract($_POST);

//set POST variables
$url = 'http://api.example.com/api';
$fields = array(
            'username' => "annonymous",
            'api_key' => urlencode("1234"),
            'images' => array(
                 urlencode(base64_encode('image1')),
                 urlencode(base64_encode('image2'))
            )
        );

//url-ify the data for the POST
$fields_string = http_build_query($fields);

//open connection
$ch = curl_init();

//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, 1);
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);

//execute post
$result = curl_exec($ch);
echo $result;

//close connection
curl_close($ch);
?>

在声明

$fields

数组后，执行

打印（$fields）

操作，很明显这不起作用（提示：只有一个

images[]

键值对）。好的，我明白了，我应该怎么做？我已经尝试过了，但它只发送

images=array

，数组是字符串：/

var\u（$\u POST['images']

返回

string（5）“数组”1

hmm，这很奇怪。你使用了http\u build\u查询吗？如果我回显上面的$fields\u字符串，它会给我username=annonymous&api\u key=1234&images%5B0%5D=aW1hZ2Ux&images%5B1%5D=aW1hZ2UyI get

username=annonymous&api\u\u key=1234&images=Array

不，如果你真的想构建您可以手动查询字符串。但是，http\u build\u查询将使“url为帖子提供数据”部分变得不必要。提取（$\u POST）；是一个安全漏洞！请勿使用它

$fields = array(
            'username' => "annonymous",
            'api_key' => urlencode("1234"),
            'images' => array(
                 urlencode(base64_encode('image1')),
                 urlencode(base64_encode('image2'))
            )
        );
$fields_string = http_build_query($fields);

<?php
//extract data from the post
extract($_POST);

//set POST variables
$url = 'http://api.example.com/api';
$fields = array(
            'username' => "annonymous",
            'api_key' => urlencode("1234"),
            'images' => array(
                 urlencode(base64_encode('image1')),
                 urlencode(base64_encode('image2'))
            )
        );

//url-ify the data for the POST
$fields_string = http_build_query($fields);

//open connection
$ch = curl_init();

//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, 1);
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);

//execute post
$result = curl_exec($ch);
echo $result;

//close connection
curl_close($ch);
?>

    $ch = curl_init();

    $data = array(
        'client_id' => 'xx',
        'client_secret' => 'xx',
        'redirect_uri' => $x,
        'grant_type' => 'xxx',
        'code' => $xx,
    );

    $data = http_build_query($data);

    curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
    curl_setopt($ch, CURLOPT_URL, "https://example.com");
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_POST, 1);

    $output = curl_exec($ch);