Php 在mysql中将日期从一个表复制到另一个表并更改格式
我正在尝试将日期(Y-m-d)从一个数据库表复制到另一个数据库表,格式为(Y-m-d H:I:s),代码如下:Php 在mysql中将日期从一个表复制到另一个表并更改格式,php,mysql,date,Php,Mysql,Date,我正在尝试将日期(Y-m-d)从一个数据库表复制到另一个数据库表,格式为(Y-m-d H:I:s),代码如下: <?php $host = "host"; $user = "user"; $password = "pass"; $database1 = "home"; $database2 = "teste"; $con1 = mysqli_connect($host, $user, $password, $database1); mysqli_set_cha
<?php
$host = "host";
$user = "user";
$password = "pass";
$database1 = "home";
$database2 = "teste";
$con1 = mysqli_connect($host, $user, $password, $database1);
mysqli_set_charset($con1, 'utf8');
if (!$con1) {die(mysqli_connect_error($con1));}
$select = "SELECT * FROM table1";
$result = mysqli_query($con1, $select) or die(mysqli_error($con1));
while($row = mysqli_fetch_assoc($result)) {
$id_product = $row[prod_id];
$date = date_create_from_format('Y-m-d', '$row[date]');
$date_add = date_format($date, 'Y-m-d H:i:s');
$con2 = mysqli_connect($host, $user, $password, $database2);
mysqli_set_charset($con2, 'utf8');
if (!$con2) {die(mysqli_connect_error($con2));}
$ins = "INSERT INTO `table2` (id_product, date_add) VALUES ('$id_product',$date_add)";
$mysq = mysqli_query($con2, $ins) or die(mysqli_error($con2));
}
?>
您只需执行以下操作:
INSERT INTO `table2` (id_product, date_add)
SELECT prod_id, date
FROM table1;
如果date
是date
数据类型,并且date\u add
是datetime
,则时间部分将被添加并自动设置为午夜。首先,您的代码有几个问题。一个像样的IDE会在编辑器中向您展示这一点
代码问题
在确保连接已建立之前,您正在尝试使用连接设置字符集
if (!$con1)
{
die(mysqli_connect_error($con1));
}
mysqli\u connect\u error()
$id_product = $row[prod_id];
没有常数产品id
。你的意思是$id\u product=$row['prod\u id']代码>取而代之
$date = date_create_from_format('Y-m-d', '$row[date]');
您试图从文本字符串'$row[date]'
生成日期,而不是从数据库中获取的日期,即$row['date']
$con2 = mysqli_connect($host, $user, $password, $database2);
您正在为每个记录创建一个新的数据库连接,而不用在使用后关闭它
$ins = "INSERT INTO `table2` (id_product, date_add) VALUES ('$id_product',$date_add)";
$date\u add
是一个字符串,需要引用
你的问题
如果您在数据库表中使用了正确的类型,MySQL将自动将00:00:00
添加到日期,因此您不需要直接解决这个问题,正如Gordon Linoff所述
如果不是这样,日期仍然作为字符串传输,因此简单的字符串连接解决了这个问题
$date_add = $row['date'] . ' 00:00:00';
重构代码
在建议的清理之后,您的代码如下所示(并执行您想要的操作):
$date_add = $row['date'] . ' 00:00:00';
<?php
$host = "host";
$user = "user";
$password = "pass";
$database1 = "home";
$database2 = "teste";
$source = mysqli_connect($host, $user, $password, $database1) or die(mysqli_connect_error());
mysqli_set_charset($source, 'utf8');
$target = mysqli_connect($host, $user, $password, $database2) or die(mysqli_connect_error());
mysqli_set_charset($target, 'utf8');
$sql = "SELECT * FROM table1";
$result = mysqli_query($source, $sql) or die(mysqli_error($source));
while ($row = mysqli_fetch_assoc($result))
{
$id = $row['prod_id'];
$date = $row['date'] . ' 00:00:00';
$sql = "INSERT INTO `table2` (id_product, date_add) VALUES ('$id','$date')";
mysqli_query($target, $sql) or die(mysqli_error($target));
}
mysqli_close($target);
mysqli_close($source);