Php 查询不'；t在数据库中插入值

在我的查询中，update语句不起作用，给出的错误是：

参数的数目与准备的语句不匹配

这是我的代码：

public function update_resource($resource)
{
    $mysqli = new MySQLi(HOST, USERNAME, PASSWORD, DATABASE);

    $this->connection_state($mysqli); 

    $id = $resource['id'];
    $descrizione = $resource['descrizione'];
    $sigla =       $resource['sigla'];
    $colore =      $resource['colore'];
    $planning =    $resource['planning'];

    try
    {   
        $query =    "UPDATE risorse SET descrizione = '$descrizione'
                        AND sigla = '$sigla' AND colore = '$colore' AND planning = '$planning'
                        WHERE id = '$id' ";

        $stmt = $mysqli->prepare($query);
        $stmt -> bind_param("ssssi", $descrizione, $sigla, $colore, $planning, $id);
        echo $query;

        if($stmt->execute())
        {
            echo "Added!";
        }
        else
        {
            echo "Err: " . $stmt->error;    
        }

    }catch(Exception $e){   echo $e->getMessage();      }

}

---

代码进入添加的条件，但查询失败，有什么问题？

您的问题是查询中没有任何占位符。 请参阅，了解如何设置占位符

通常，占位符是

？

，稍后将用值替换，因此您的查询应该如下所示：

$query = "UPDATE risorse SET descrizione = ?
                    AND sigla = ? AND colore = ? AND planning = ?
                    WHERE id = ?";

---

请在得到答案后访问。请参见示例#1执行一个带有命名占位符的准备好的语句

它应该是$query=“UPDATE risorse SET Descriptione=？，sigla=？，colore=？，planning=？WHERE id=？”；我现在对这个有点生疏了，你能给我看看吗？

public function update_resource($resource)
{
    $mysqli = new mysqli(HOST, USERNAME, PASSWORD, DATABASE);

    if ($mysqli->connect_errno) {
        echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
    }

    $id = $resource['id'];
    $descrizione = $resource['descrizione'];
    $sigla =       $resource['sigla'];
    $colore =      $resource['colore'];
    $planning =    $resource['planning'];

    try
    {   
        $query =    "UPDATE risorse SET descrizione = '$descrizione'
                        , sigla = '$sigla', colore = '$colore', planning = '$planning'
                        WHERE id = '$id' ";

        $stmt = $mysqli->prepare($query);
        $stmt -> bind_param($descrizione, $sigla, $colore, $planning, $id);
        echo $query;

        if($stmt->execute())
        {
            echo "Added!";
        }
        else
        {
            echo "Err: " . $stmt->error;    
        }

    }catch(Exception $e){   echo $e->getMessage();      }

}?