Php MySQL多对多过滤器

我对以下表格进行了多对多分析：

1） 收据

2） 配料

-id
-name

-recept_id
-ingredient_id

3） 收据成分

-id
-name

-recept_id
-ingredient_id

现在我想找到有配料清单的收据。例如，所有含有“番茄”和“香蒜酱”成分的收据。（而不是只有“西红柿”或“香蒜酱”的收据。查询结果会是什么样子？

试试这个

SELECT * FROM 
(SELECT * FROM ingredients AS i 
LEFT JOIN `receipts-ingredients` AS ri ON i.id=ri.ingredient_id 
LEFT JOIN receipts AS r ON ri.recept_id=r.id 
WHERE i.name='tomato') AS Tomato, JOIN 
(SELECT * FROM ingredients AS i 
LEFT JOIN `receipts-ingredients` AS ri ON i.id=ri.ingredient_id 
LEFT JOIN receipts AS r ON ri.recept_id=r.id 
WHERE i.name='pesto') AS Pesto ON Tomato.recept_id=Pesto.recept_id

SELECT r.id, r.name, GROUP_CONCAT(DISTINCT(i.name)) as items
 FROM receipts r
 LEFT JOIN receipts-ingredients ri ON(ri.receipt_id = r.id)
 LEFT JOIN ingredients i ON(ri.ingredient_id = i.id)
 GROUP BY r.id
 HAVING FIND_IN_SET('tomato',items) AND FIND_IN_SET('pesto',items)

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在荷兰董事会上找到了另一个可行的答案：

SELECT
    r.id,
    r.name
FROM
    receipts r
JOIN
    receipts_ingredients ri
    ON r.id = ri.receipt_id
JOIN
    ingredients i
    ON ri.ingredient_id = i.id
WHERE i.name IN ('tomato', 'pesto')
GROUP BY r.id
HAVING COUNT(*) = 2

---

这是一种硬编码方法（有更好的答案），但您也可以将其用于特定数据（仅供参考：我在“收据成分”表的“收据id”列添加了字符“i”）

编辑

此外，您可能需要在receipts Components表名称周围加上反勾。也许将其重命名为receipts\u Components是个好主意

SELECT aa.id, aa.name AS receipts_name
FROM receipts AS aa
INNER JOIN `receipts-ingredients` AS bb
ON aa.id = bb.receipt_id
INNER JOIN ingredients AS cc
ON cc.id = bb.ingredient_id
INNER JOIN (
    SELECT aa.id
    FROM receipts AS aa
    INNER JOIN `receipts-ingredients` AS bb
    ON aa.id = bb.receipt_id
    INNER JOIN ingredients AS cc
    ON cc.id = bb.ingredient_id
    WHERE cc.name = 'pesto' 
) _aa
ON aa.id = _aa.id
WHERE cc.name = 'tomato'

---

要么是自连接，要么是分组方式。（学校作业？）这意味着一个子查询？@FrankBee看到QueryTank你了，但是你的查询只给出了“西红柿”或“香蒜酱”的结果。哦，你必须连接两个子查询。editet查询应该非常有效@FrankbeenThank you。它给出了我需要的结果集。比我想象的更复杂。