Plsql PL/SQL、CASE语句或if语句

我是PL/SQL新手

我有这样的代码

SELECT f.code,f.date,f.amt, row_number() OVER (PARTITION BY f.code ORDER BY f.date DESC) ranki
FROM advance.alloc f

和显示

 CODE   DATE      AMT ranki
    122 12/31/2016 3   1
    122 12/31/2015 7   2
    122 12/31/2014 3   3
    123  6/30/2015 3   1
    125  6/30/2015 2   1
    125 12/31/2014 8   2

这是什么逻辑

if DATE = 12/__/__  AND ranki = 1 THEN ranki 1, so 122 picks 12/31/2016 3
if DATE = 6/30/__  AND ranki = 1  AND if ranki = 2 exists THEN  then pick the second one,so 125 picks 12/31/2014 8
if 6/30__ and ranki is ONLY 1 shows Blank on date LIKE 123

所以我想展示一下

   122 12/31/2016 3 
   123 __________ 3 
   125 12/31/2014 8

如何编写类似于PL/SQL的代码

WHEN to_char(af.date,'MM') = 12 AND af.ranki = 1 THEN af.date END

我可以编写第一个逻辑，但我不知道如何编写其余的逻辑

---

谢谢

为什么使用PL/SQL？还是说“在Oracle SQL中”？（以下解决方案使用标准分析函数，因此它不是Oracle特有的。）

除了

ranki

之外，还可以通过分析函数添加更多信息。从带有

ranki=1

的行中提取月份，以及每个

code

的总计数。然后WHERE子句可以逐步遵循您的逻辑

with
     f ( code, dt, amount ) as (
       select 122, to_date('12/31/2016', 'mm/dd/yyyy'), 3 from dual union all
       select 122, to_date('12/31/2015', 'mm/dd/yyyy'), 7 from dual union all
       select 122, to_date('12/31/2014', 'mm/dd/yyyy'), 3 from dual union all
       select 123, to_date( '6/30/2015', 'mm/dd/yyyy'), 3 from dual union all
       select 125, to_date( '6/30/2015', 'mm/dd/yyyy'), 2 from dual union all
       select 125, to_date('12/31/2014', 'mm/dd/yyyy'), 8 from dual
     )
-- End of simulated data (for testing purposes only, not part of the solution).
-- SQL query begins BELOW THIS LINE.
select code, case when mth = 12 or ranki = 2 then dt end as dt, amount
from   ( select code, dt, amount,
                first_value(extract (month from dt)) 
                             over (partition by code order by dt desc) as mth,
                row_number() over (partition by code order by dt desc) as ranki,
                count(*)     over (partition by code)                  as cnt
         from   f
       )
where mth = 12 and ranki = 1
   or cnt =  1
   or mth =  6 and ranki = 2
;

CODE DT         AMOUNT
---- ---------- ------
 122 12/31/2016      3
 123                 3
 125 12/31/2014      8

---

为什么使用PL/SQL？还是说“在Oracle SQL中”？（以下解决方案使用标准分析函数，因此它不是Oracle特有的。）

除了

ranki

之外，还可以通过分析函数添加更多信息。从带有

ranki=1

的行中提取月份，以及每个

code

的总计数。然后WHERE子句可以逐步遵循您的逻辑

with
     f ( code, dt, amount ) as (
       select 122, to_date('12/31/2016', 'mm/dd/yyyy'), 3 from dual union all
       select 122, to_date('12/31/2015', 'mm/dd/yyyy'), 7 from dual union all
       select 122, to_date('12/31/2014', 'mm/dd/yyyy'), 3 from dual union all
       select 123, to_date( '6/30/2015', 'mm/dd/yyyy'), 3 from dual union all
       select 125, to_date( '6/30/2015', 'mm/dd/yyyy'), 2 from dual union all
       select 125, to_date('12/31/2014', 'mm/dd/yyyy'), 8 from dual
     )
-- End of simulated data (for testing purposes only, not part of the solution).
-- SQL query begins BELOW THIS LINE.
select code, case when mth = 12 or ranki = 2 then dt end as dt, amount
from   ( select code, dt, amount,
                first_value(extract (month from dt)) 
                             over (partition by code order by dt desc) as mth,
                row_number() over (partition by code order by dt desc) as ranki,
                count(*)     over (partition by code)                  as cnt
         from   f
       )
where mth = 12 and ranki = 1
   or cnt =  1
   or mth =  6 and ranki = 2
;

CODE DT         AMOUNT
---- ---------- ------
 122 12/31/2016      3
 123                 3
 125 12/31/2014      8