使用PostgreSQL中的子查询进行更新不起作用

我使用的是Postgresql 9.3，但此SQL不起作用：

UPDATE revision_table
SET (code, uuid, converted_entity1uuid, converted_entity1code) = 
         (SELECT convertedT.code, convertedT.uuid, convertedT.uuid, convertedT.code
          FROM currency convertedT 
          INNER JOIN currency_conversion_aud conversionT ON conversionT.currency1_id = convertedT.id
          WHERE conversionT.id = 125
          ORDER BY rev DESC LIMIT 1), 
    (converted_entity2uuid, converted_entity2code) = 
         (SELECT convertedT.uuid, convertedT.code 
          FROM currency convertedT 
          INNER JOIN currency_conversion_aud conversionT ON conversionT.currency2_id = convertedT.id
          WHERE conversionT.id = 125
          ORDER BY rev DESC LIMIT 1) 
WHERE id = 12;

错误：

错误：选择位置或附近出现语法错误 LIGNE 3:选择convertedT.code、convertedT.uuid

但如果我在postgres 9.6中运行此SQL，它可以正常工作：

UPDATE revision_table
SET (code, uuid, converted_entity1uuid, converted_entity1code) = 
         (SELECT convertedT.code, convertedT.uuid, convertedT.uuid, convertedT.code
          FROM currency convertedT 
          INNER JOIN currency_conversion_aud conversionT ON conversionT.currency1_id = convertedT.id
          WHERE conversionT.id = 12
          ORDER BY rev DESC LIMIT 1), 
    (converted_entity2uuid, converted_entity2code) = 
         (SELECT convertedT.uuid, convertedT.code 
          FROM currency convertedT 
          INNER JOIN currency_conversion_aud conversionT ON conversionT.currency2_id = convertedT.id
          WHERE conversionT.id = 12 
          ORDER BY rev DESC LIMIT 1) 
WHERE id = 12;

UPDATE 0
Temps : 75,359 ms

我如何转换为与9.3兼容，因为9.3中有生产

感谢您的帮助

最终解决：

UPDATE 
  revision_table
SET
  code = sub1.code, 
  uuid = sub1.uuid,
  converted_entity1uuid = sub1.uuid,
  converted_entity1code = sub1.code,
  converted_entity2uuid=sub2.uuid,
  converted_entity2code=sub2.code
FROM (
  SELECT convertedT.code, convertedT.uuid
  FROM currency convertedT 
  INNER JOIN currency_conversion_aud conversionT
    ON conversionT.currency1_id = convertedT.id
  WHERE conversionT.id = 12
  ORDER BY rev DESC LIMIT 1
) sub1,
(
  SELECT convertedT.uuid, convertedT.code 
  FROM currency convertedT 
  INNER JOIN currency_conversion_aud conversionT
    ON conversionT.currency2_id = convertedT.id
  WHERE conversionT.id = 12 
  ORDER BY rev DESC LIMIT 1
)  sub2
WHERE id = 12;

---

升级到Postgres 9.6，这是最简单的方法。老实说，即使是9.6现在已经有好几年的历史了，而且可能也不会永远得到支持。Postgres 9.3是说你应该尽快计划升级。@TimBiegeleisen:这里记录了它的生命周期：你可以将它重写为更新。。。设置从…起但是你的代码真的很难理解。@TimBiegeleisen，我同意，但现在不可能，我已经用语法中的更新集重写了，谢谢