PostgreSql 12 JDBC多结果集,只能获取第一个结果集
希望JDBC从PostgreSql 12函数中获取多个结果集。JDBC版本org.postgresql/postgresql/42.2.9。PostgreSql函数如下所示:PostgreSql 12 JDBC多结果集,只能获取第一个结果集,postgresql,jdbc,multiple-resultsets,Postgresql,Jdbc,Multiple Resultsets,希望JDBC从PostgreSql 12函数中获取多个结果集。JDBC版本org.postgresql/postgresql/42.2.9。PostgreSql函数如下所示: create or replace function test() returns setof refcursor as $$ declare ret1 refcursor; ret2 refcursor; begin open ret1 for select 10 as a; re
create or replace function test()
returns setof refcursor as $$
declare
ret1 refcursor;
ret2 refcursor;
begin
open ret1 for
select 10 as a;
return next ret1;
open ret2 for
select 20 as b;
return next ret2;
end; $$ language plpgsql;
Java代码如下所示:
stmt = getConnection().prepareCall("{ ? = call test() }");
stmt.registerOutParameter(1, Types.OTHER);
stmt.execute();
rs = (ResultSet)stmt.getObject(1);
if (rs.next()) {
int a = rs.getInt("a");
if (rs.next()) {
int b = rs.getInt("b");
}
}
已成功检索“a”,但第二个“rs.next()”返回false。谷歌搜索了很多,但都没能成功。如何获得第二个结果集?这对我帮助很大,问题得到了解决
...
out ret1 refcursor,
out ret2 refcursor)
returns record as $$
begin
open ret1 for select 10;
open ret2 for select 20;
end; $$ language plpgsql;
爪哇:
stmt = getConnection().prepareCall("{call test(?,?)}");
stmt.registerOutParameter(1, Types.OTHER);
stmt.registerOutParameter(2, Types.OTHER);
stmt.execute();
ResultSet rs1 = (ResultSet)stmt.getObject(1);
ResultSet rs2 = (ResultSet)stmt.getObject(2);
int a = 0, b = 0;
if (rs1.next()) {
a = rs1.getInt(1);
}
if (rs2.next()) {
b = rs2.getInt(1);
}