如何在postgreSQL中执行此SQL查询?
如何在PostgreSQL中执行此查询 我在SQL中的尝试如何在postgreSQL中执行此SQL查询?,postgresql,Postgresql,如何在PostgreSQL中执行此查询 我在SQL中的尝试 SELECT stories.* where user.id = 1 AND user.id = usersources.userid AND usersources.id = source.id AND source.id = story.id AND (story.id = user.id
SELECT stories.*
where
user.id = 1 AND
user.id = usersources.userid AND
usersources.id = source.id AND
source.id = story.id
AND (story.id = user.id) IS NOT IN actions table
文本解释
SELECT
stories
WHERE
they have a relationship to a source AND
sources has a story AND
there IS NOT a row in actions from user and story (aka already acted on story)
上下文
SELECT
stories
WHERE
they have a relationship to a source AND
sources has a story AND
there IS NOT a row in actions from user and story (aka already acted on story)
这是一个用户可以订阅多个新闻源的应用程序
浏览新闻。一旦用户浏览新闻,他们就不能再浏览了
再次看到那个新闻报道
表格的视觉效果
好的,我想这会让你达到你的标准
SELECT s.*
FROM stories s
INNER JOIN actions a ON s.id = a.storyid
INNER JOIN sources s1 ON s.id = s1.id
INNER JOIN usersources us ON s1.id = us.sourceid
INNER JOIN users u ON us.userid = u.id
WHERE u.id = 1
AND u.id != a.userid
好的,我想这会让你达到你的标准
SELECT s.*
FROM stories s
INNER JOIN actions a ON s.id = a.storyid
INNER JOIN sources s1 ON s.id = s1.id
INNER JOIN usersources us ON s1.id = us.sourceid
INNER JOIN users u ON us.userid = u.id
WHERE u.id = 1
AND u.id != a.userid
我闻到了家庭作业的味道不:)这实际上是我的iOS应用程序。我想今天发布,但我有一个黑客的方式和300毫秒的响应时间:D只是想澄清这个问题。我闻到了家庭作业的味道否:)这实际上是我的iOS应用程序。我想今天发布,但我有一个黑客方式,响应时间为300ms:D,只是想澄清这个问题。我认为你需要
左连接动作
或不存在()
,因为现在你要求这个故事已经有人演过了,只是不是通过u.id=1
。hmmm似乎没有返回任何内容:(我认为您需要左连接操作或不存在()
,因为现在您要求该故事已经由某人执行,而不是通过u.id=1
。hmmm似乎没有返回任何内容:(