必须从我的postgresql查询中找到行数

嗨，我试图从下面的查询中获取行数：

        select count(substring(wsresult_question FROM '[0-9]+') as pumporder) AS totals,
            job_id,
            job_siteid,
            job_completed
            from webserviceresults w, jobs s 
            where job_siteid = '1401' 
            and job_id = wsresult_jobid
            and job_completed is not null
            and wsresult_question LIKE 'job.job_site_data.site_meters.pump.%' 
            and wsresult_category = 'Job' 
            group by pumporder,job_id,job_siteid,job_completed order by job_completed desc

我试过了，我得到了这样的错误

There was an SQL error: 
ERROR: syntax error at or near "as" LINE 1: ... count(substring(wsresult_question FROM '[0-9]+') as pumpord... ^

在这行

子字符串（wsresult_question FROM'[0-9]+'）中，作为pumporder

我只想从一些串联字符串中获取一个数字。连接字符串如下所示

1.job.job\u site\u data.site\u meters.pump.0.meter\u calibration\u record.meter\u adjusted of ast

2.job.job\u site\u data.site\u meters.pump.0.meter\u calibration\u record.meter\u adjusted tolow

3.job.job\u site\u data.site\u meters.pump.1.meter\u calibration\u record.meter\u adjusted of ast

因此，

substring（wsresult_question FROM'[0-9]+'）作为pumporder

返回数组中类似于0,1的数字。我现在需要合计行数。所以，请在这方面帮助我

如果您有任何疑问，请告诉我

---

提前谢谢

您的错误意味着您不应该为函数创建别名-仅为列创建别名，因此如果您将

作为pumporder

从

计数（子字符串（来自“[0-9]+”）作为pumporder）

中删除，错误将消失

不过你的方法很可疑。如果要使用

子字符串（wsresult\u问题来自“[0-9]+”）

计算行数，最好：

    select count(1) AS totals,
        job_id,
        job_siteid,
        job_completed
        from webserviceresults w, jobs s 
        where job_siteid = '1401' 
        and job_id = wsresult_jobid
        and job_completed is not null
        and wsresult_question  ~ '^(job.job_site_data.site_meters.pump.)[0-9]' 
        and wsresult_category = 'Job' 
        group by pumporder,job_id,job_siteid,job_completed order by job_completed desc

最后一个字符串

job.job\u site\u data.site\u meters.pump.0

看起来像json路径，因此使用json数组长度函数更合适，而不是计算行数