更新文档库中现有记录的ContentType的PowerShell脚本
我们正在SharePoint 2010环境中使用文档库。文档库中大约有200个文档已被识别(基于位置-英格兰和员工类型-FT),现在我必须将这200个文档的内容类型更改为新的内容类型“new FT”。我正在使用下面的powershell代码-更新文档库中现有记录的ContentType的PowerShell脚本,powershell,sharepoint-2010,document-library,sharepointdocumentlibrary,Powershell,Sharepoint 2010,Document Library,Sharepointdocumentlibrary,我们正在SharePoint 2010环境中使用文档库。文档库中大约有200个文档已被识别(基于位置-英格兰和员工类型-FT),现在我必须将这200个文档的内容类型更改为新的内容类型“new FT”。我正在使用下面的powershell代码- $webUrl = "http://www.site.com/sites/Library/" $web = Get-SPWeb -Identity $webUrl $list = $web.Lists["CURRENT FTE"] $spQuery =
$webUrl = "http://www.site.com/sites/Library/"
$web = Get-SPWeb -Identity $webUrl
$list = $web.Lists["CURRENT FTE"]
$spQuery = New-Object Microsoft.SharePoint.SPQuery
$spQuery.ViewAttributes = "Scope='Recursive'";
$spQuery.ListItemCollectionPosition = $listItems.ListItemCollectionPosition
foreach($item in $listItems)
{
$lookup = [Microsoft.SharePoint.SPFieldLookupValue]$item["ROLE"];
$role = $lookup.LookupValue;
$EMPTYPE = $item["EMP TYPE"]
$lookup4 = [Microsoft.SharePoint.SPFieldLookupValue]$item["Location"];
$LOCATION = $lookup4.LookupValue;
$ContentTypeName = $item.ContentType.Name
$ContentTypeID = $item.ContentType.Id
if ($LOCATION -eq "England")
{
if($EMPTYPE -eq "FT")
{
#CheckList - 1
Write-Output "ID - $($item.id) "
Write-Output "Name - $($item.name)"
Write-Output "Role - $($role) "
Write-Output "emptype - $($EMPTYPE) "
Write-Output "location - $($LOCATION) "
Write-Output "Content Type Name - $($ContentTypeName) "
Write-Output "Content Type ID - $($ContentTypeID) "
Write-Output " "
$newct = $list.ContentTypes["New FT"]
$newctid = $newct.ID
If (($newct -ne $null) -and ($newctid -ne $null))
{
$item["ContentTypeId"] = $newctid
$item.Update()
$newContentTypeName = $item.ContentType.Name
$newContentTypeID = $item.ContentType.Id
#CheckList - 2
Write-Output "ID - $($item.id) "
Write-Output "Name - $($item.name)"
Write-Output "Role - $($role) "
Write-Output "emptype - $($EMPTYPE) "
Write-Output "location - $($LOCATION) "
Write-Output "Content Type Name - $($newContentTypeName) "
Write-Output "Content Type ID - $($newContentTypeID) "
Write-Output " "
}
}
}
}
现在,代码标识每个文档/记录,然后按照清单-1中列出的方式打印详细信息,然后我进行更新并尝试打印清单-2中的新更新值,但问题是清单-2没有打印更新的内容类型和更新的内容类型ID($newContentTypeName,$newContentTypeID)
我是不是做错了什么,请告诉我!(如有必要,请随时更新代码)在上面“Yevgeniy.Chernobrivets”评论的帮助下,我能够使所有字段都出现在清单-2中。根据我的评论,我必须做以下工作-
$updateItem = $list.GetItemById($item.ID);
$contentTypeID = $updateItem.ContentType.Id
$contentTypeName = $updateItem.ContentType.Name
更新后是否尝试打印$item[“ContentTypeId”]值?对吗?你也试过买新的吗?类似于$updateItem=$list.GetItemById($item.ID)$updateItem.ContentType.Id