Python 2.7 在Python2.7中使用以参数命名的关键字参数进行闭包

我需要在运行时动态声明具有任意数量命名参数（关键字）的funktion，以便其他库可以使用字典作为参数调用此函数。以下是我需要的一个示例：

def generateFunction(*kwrds):
  #kwrds are a bunch of strings
  def functionTheLibraryCalls('''an argument for every string in kwrds '''):
    #Get all arguments in a tuple in the order as listed above
    result = tuple(args)
    #Code that needs to be executed inside the library,
    #it can handle a variable number of arguments
    return result
  return functionTheLibraryCalls


f1 = generateFunction('x', 'y','z')
print f1(x = 3,y = 2, z = 1)
#>> (3,2,1)
f2 = generateFunction('a', 'b')
print f2(a = 10, b = 0)
#>> (10,0)

这在Python2.7中可能吗？f1和f2的参数实际上将作为dict传递。如果lambda更适合于此，也可以

谢谢大家!

这就是你想要的

def generateFunction(*names):
    #kwrds are a bunch of strings
    def functionTheLibraryCalls(**kwrds):
        #Code that needs to be executed inside the library,
        #it can handle a variable number of arguments
        print names, kwrds
        return 42
    return functionTheLibraryCalls

实际上，你甚至可以删除

*名称。
这就是你想要的吗

def generateFunction(*names):
    #kwrds are a bunch of strings
    def functionTheLibraryCalls(**kwrds):
        #Code that needs to be executed inside the library,
        #it can handle a variable number of arguments
        print names, kwrds
        return 42
    return functionTheLibraryCalls

实际上，您甚至可以删除
*名称