Python 3.x Tkinter在初始化后更改跟踪OptionMenu的StringVar

Python 3.x Tkinter在初始化后更改跟踪OptionMenu的StringVar,python-3.x,tkinter,optionmenu,Python 3.x,Tkinter,Optionmenu,如果可能的话,我不知道如何将不同的StringVar分配给已经存在的OptionMenu 例如: def optionMenuChanged(*args): print(args[0]) # prints var1 if assigned to foo, prints var2 if assigned to bar foo = tk.StringVar(name = 'var1') foo.trace('w', optionMenuChanged) bar = tk.StringVar(

如果可能的话,我不知道如何将不同的StringVar分配给已经存在的OptionMenu

例如:

def optionMenuChanged(*args):
    print(args[0]) # prints var1 if assigned to foo, prints var2 if assigned to bar
foo = tk.StringVar(name = 'var1')
foo.trace('w', optionMenuChanged)
bar = tk.StringVar(name = 'var2')
bar.trace('w', optionMenuChanged)
choices = ['1', '2', '3']
menu = OptionMenu(frame, foo, *choices)
'''
do stuff with menu
'''
menu.SetVariable(bar) # SetVariable does not exist
'''
do other stuff with menu
'''
这可能吗?

是的,可能会,但很棘手

  • 首先定义一个函数,如下所示:
    def set_var(optmenu, var, callback=None):
        menu = optmenu['menu']
        last = menu.index('end')
        for i in range(last+1):
            label = menu.entrycget(i, 'label')
            menu.entryconfig(i, command=tk._setit(var, label, callback))
        optmenu.config(textvariable=var)
    
  • 然后,只要您想更改变量,就调用它:
    set_var(menu, bar)
    

你在找这样的东西吗?