Python 3.x 回文和语法错误?
我们如何创建一个程序来检查我们给出的输入(例如:example)是否具有相同的长度和相同的字母(例如)?这是一个高效的python代码Python 3.x 回文和语法错误?,python-3.x,Python 3.x,我们如何创建一个程序来检查我们给出的输入(例如:example)是否具有相同的长度和相同的字母(例如)?这是一个高效的python代码 NO_OF_CHARS = 256 def areAnagram(str1, str2): # Create two count arrays and initialize all values as 0 count1 = [0] * NO_OF_CHARS count2 = [0] * NO_OF_CHARS # For e
NO_OF_CHARS = 256
def areAnagram(str1, str2):
# Create two count arrays and initialize all values as 0
count1 = [0] * NO_OF_CHARS
count2 = [0] * NO_OF_CHARS
# For each character in input strings, increment count
# in the corresponding count array
for i in str1:
count1[ord(i)]+=1
for i in str2:
count2[ord(i)]+=1
# If both strings are of different length. Removing this
# condition will make the program fail for strings like
# "aaca" and "aca"
if len(str1) != len(str2):
return 0
# Compare count arrays
for i in xrange(NO_OF_CHARS):
if count1[i] != count2[i]:
return 0
return 1
str1 = "EXAMPLE"
str2 = "XAMPLEE"
if areAnagram(str1, str2):
print "The two strings are anagram of each other"
else:
print "The two strings are not anagram of each other"
导入数组
word1=“示例”
word2=“示例”
字母=数组。数组('i',(0,)*26)
#数一数单词1的字母
对于word1中的c:
charIndex=ord(c)-ord('A')
字母[charIndex]=字母[charIndex]+1
#计算单词2的字母数并从单词1中减去它们
对于word2中的c:
charIndex=ord(c)-ord('A')
字母[charIndex]=字母[charIndex]-1
#如果单词相同,则字母仅包含0
如果字母数(0)<26:
打印(“文字不同”)
其他:
打印(“单词是字谜”)
请向我们提供您编写和尝试的代码,并更具体地说明您在使用此代码时遇到的问题。
import array
word1 = "EXAMPLE"
word2 = "XAMPLEE"
letters = array.array('i',(0,)*26)
# Count letters of word1
for c in word1:
charIndex = ord(c) - ord('A')
letters[charIndex] = letters[charIndex]+1
# Count letters of word2 and substract them from word1 count
for c in word2:
charIndex = ord(c) - ord('A')
letters[charIndex] = letters[charIndex]-1
# letters contains only 0 if words are the same
if letters.count(0) < 26:
print("Words are different")
else:
print("Words are anagrams")