在python中使用random.randint帮助
下面的代码是我模拟彩票的尝试在python中使用random.randint帮助,python,Python,下面的代码是我模拟彩票的尝试 import random def lottery(numbers): lottoNumbers = [randint('0,100') for count in range(3)] if numbers == lottoNumbers: print('YOU WIN $10,000') else: print('YOU LOSE,DUN DUN DUNNN!') return numbers
import random
def lottery(numbers):
lottoNumbers = [randint('0,100') for count in range(3)]
if numbers == lottoNumbers:
print('YOU WIN $10,000')
else:
print('YOU LOSE,DUN DUN DUNNN!')
return numbers
def main():
numbers = int(input('Enter a number: '))
if numbers == lottoNumbers:
numbers = lottery(numbers)
else:
numbers = lottery(numbers)
main()
嘿,伙计们,在你们的帮助下,我走了这么远。我正在尝试编写代码,以便随机选择3个乐透号码。然后用户必须输入他/她自己的3个乐透号码。如果他们全部3个数字都正确,那么他们将赢得全部奖金;如果他们获得3个数字,但顺序不正确,那么他们将赢得部分奖金。显然,如果他们猜错了,那么一份书面声明就会说明这一点。我感到困惑的是,如何编写代码,以便用户可以输入3个数字来尝试匹配随机彩票号码。我还想在用户输入他/她的选择后打印3个彩票号码。有什么想法吗,伙计们
谢谢大家的帮助。试着发布你的全部代码。在发布时还要注意缩进,在那里,函数的定义看起来是空的 我会这样做:
import random
def lottery():
win = True
for i in range(3):
guess = random.randint(1,100)
if int(raw_input("Please enter a number...")) != guess:
win = False
break
return win
from random import randint
def doLotto(numbers):
# make the lotto number list
lottoNumbers = [randint(0,100) for x in range(len(numbers))]
# check to see if the numbers were equal to the lotto numbers
if numbers == lottoNumbers:
print("You are WinRar!")
else:
print("You Lose!")
对于函数中参数的作用,您似乎有点困惑。你说过你的randm函数接受参数“number”,但实际上你没有在任何地方使用它。下一次出现数字时,您已经为其分配了一个全新的值,因此传递给randm的任何值实际上都不会被使用 此外,函数试图返回x,而x尚未在函数中赋值。要么已经定义了一个名为x的全局变量,在这种情况下,函数将只返回该变量,要么函数将因为找不到变量x而失败 这里有一个我已经做过的简单例子,你把它们的三个数字作为一个列表作为一个参数传递给函数
import random
theirNumbers=[5,24,67]
def checkNumbers(theirNumbers):
lottoNumbers = []
for count in range(3)
lottoNumbers.append(random.randint(0,100))
winning = True
for number in theirNumbers:
if not each in lottoNumbers: winning=False
if winning == True: print("Winner!")
仅举几个例子,您的实现存在一些问题: 如果试图将函数
randm
的输出与x进行比较,则需要在函数中包含一个返回值,如下所示:
def randm():
return return_value
您似乎正在打印所有值,但没有存储它们,最后您只会得到最后一个值,您应该尝试将它们存储在如下列表中:
list_name = [randint(0,100) for x in range(x)]
这将在列表中生成randint(0100)
x
次,这将允许您稍后访问所有值
要将您的代码修复为尽可能接近您尝试的代码,我将执行以下操作:
import random
def randm(user_numbers):
number = []
for count in range(3):
number.append(random.randint(0, 100))
print(number)
return user_numbers == number
if randm(x):
print('WINNER')
如果你正在寻找一种非常适合做这项工作的方法, 您可能想尝试以下方法:
import random
def lottery():
win = True
for i in range(3):
guess = random.randint(1,100)
if int(raw_input("Please enter a number...")) != guess:
win = False
break
return win
from random import randint
def doLotto(numbers):
# make the lotto number list
lottoNumbers = [randint(0,100) for x in range(len(numbers))]
# check to see if the numbers were equal to the lotto numbers
if numbers == lottoNumbers:
print("You are WinRar!")
else:
print("You Lose!")
我从您的代码(特别是print()代码)中假设您正在使用python 3.x+让我们通过几个步骤来实现这一点。 在编写代码时,您应该学习的第一件事是让独立的代码段(函数或对象)执行不同的工作 首先,让我们创建用于彩票的函数:
def makeLottery(slotCount, maxNumber):
return tuple(random.randint(1,maxNumber) for slot in range(slotCount))
接下来,让我们创建一个函数来询问用户的猜测:
def askGuess(slotCount, maxNumber):
print("take a guess, write {count} numbers separated by space from 1 to {max}".format(count = self.slotCount, max = self.maxNumber))
while True: #we will ask user until he enter sumething suitable
userInput = raw_input()
try:
numbers = parseGuess(userInput,slotCount,maxNumber)
except ValueError as err:
print("please ensure your are entering integer decimal numbers separated by space")
except GuessError as err:
if err.wrongCount: print("please enter exactly {count} numbers".format(count = slotCount))
if err.notInRange: print("all number must be in range from 1 to {max}".format(max = maxNumber))
return numbers
这里我们使用另一个函数和自定义异常类,让我们创建它们:
def parseGuess(userInput, slotCount,maxNumber):
numbers = tuple(map(int,userInput.split()))
if len(numbers) != slotCount : raise GuessError(wrongCount = True)
for number in numbers:
if not 1 <= number <= maxNumber : raise GuessError(notInRange = True)
return numbers
class GuessError(Exception):
def __init__(self,wrongCount = False, notInRange = False):
super(GuessError,self).__init__()
self.wrongCount = wrongCount
self.notInRange = notInRange
正如您可以看到的,这里的许多函数都使用公共数据来工作。因此,它应该建议您在单个类中收集整个代码,让我们这样做:
class Lottery(object):
def __init__(self, slotCount, maxNumber):
self.slotCount = slotCount
self.maxNumber = maxNumber
self.lottery = tuple(random.randint(1,maxNumber) for slot in range(slotCount))
def askGuess(self):
print("take a guess, write {count} numbers separated by space from 1 to {max}".format(count = self.slotCount, max = self.maxNumber))
while True: #we will ask user until he enter sumething suitable
userInput = raw_input()
try:
numbers = self.parseGuess(userInput)
except ValueError as err:
print("please ensure your are entering integer decimal numbers separated by space")
continue
except GuessError as err:
if err.wrongCount: print("please enter exactly {count} numbers".format(count = self.slotCount))
if err.notInRange: print("all number must be in range from 1 to {max}".format(max = self.maxNumber))
continue
return numbers
def parseGuess(self,userInput):
numbers = tuple(map(int,userInput.split()))
if len(numbers) != self.slotCount : raise GuessError(wrongCount = True)
for number in numbers:
if not 1 <= number <= self.maxNumber : raise GuessError(notInRange = True)
return numbers
def askAndCheck(self):
userGuess = self.askGuess()
if self.lottery == userGuess : print "BINGO!!!!"
else : print "Sorry, you lost"
请修复
缩进
。那么您在程序中实际使用的名称是随机
、随机
和随机
?我只能建议你不要那样。嘿,谢谢你,尼克。我可以问一下为什么吗?如果用户错过了一个猜测,游戏就输了。如果他没有错过任何比赛,他就赢了。您可以随时更改代码,使程序打印一些消息,而不是返回布尔值。在我的类中,您在这段代码中使用的一些函数我还没有学到那么多。。一旦我这样做了,我会在其他作业中参考这个。谢谢