Python误解了我的列表

出于某种原因，Python不断抛出一个TCL错误，其中表示“未知颜色”，尽管它从中获取字符串的列表与颜色无关。这有什么原因吗

#Add words to this list to include them in the game
words = ["Games","Development","Keyboard","Speed","Typer","Anything","Aplha","Zealous","Accurate","Basics","Shortcut","Purpose","Window","Counter","Fortress","Modification","Computer","Science","History","Football","Basketball","Solid","Phantom","Battlefield","Avdvanced","Warfare","Download","Upload","Antidisestablishmentarianism","Supercalifragilisticexpialidocious","Discomobobulation","Liberated","Assassin","Brotherhood","Revelation","Unity","Syndicate","Victory"]

def nextWord():
        global score
        entry.focus_set()
        if entry.get().lower() == words[1].lower():
            score += 1

        entry.delete(0, tkinter.END)
        random.shuffle(words)
        label.config(fg=str(words[1]), text=str(words[0]))
        scoreLabel.config(text="Score: " + str(score))

这是新的错误：

ValueError: dictionary update sequence element #0 has length 1; 2 is required

另外，我知道我的一些/大部分代码可能不正确，我想知道如何设置最大的洗牌时间和显示字符串的时间，然后再打印标签中的所有字符串。（第二个问题，如果不想回答，不必回答）

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谢谢。

您明确告诉tkinter使用这个词作为颜色；这就是

fg

在

label.config（fg=str（words[1]），…）

行中所做的

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因为它不是一种颜色，所以不应该这样做。

如果出现异常，请发布堆栈跟踪，并确定是哪一行导致了问题。对不起，我是新来的，但我已经更改了它，所以是否可以使用其他方法来修复它或只是删除fg=str？我不明白您试图做什么。是的，如果你不想设置颜色，显然你应该删除它。我试图从列表中获取随机单词并显示在标签中，我已经删除了它，但它会抛出一个值错误，正如khelwood所说，如果你遇到错误，你应该将其与完整的回溯一起发布。