Python 当检查用户输入的内容是否与数组[i]中的内容相同时，如何每次将分数增加100？

我正在尝试创建一个游戏，用户必须回忆弹出窗口中显示的数字。在他们出错的数字中，“不正确”是由出错数字的数量增加的。如果每个数字都正确，分数将增加100。在这种情况下，应输出300作为分数。 如果用户输入的内容与

array[i]

import random

array = []

#this appends three random numbers into an empty array
for i in range(3):
    randomNumber = random.randint(0,100)
    array.append(randomNumber)

# this function displays the random number for 1250 milliseconds
def randomNumberDisplay():
    import tkinter as tk
    root = tk.Tk()
    root.title("info")
    tk.Label(root, text=array).pack()
    # time in ms
    root.after(1250, lambda: root.destroy())
    root.mainloop()   
randomNumberDisplay()


#this function requires the user to enter the numbers displayed.
score = 0
def levelOne ():
    incorrect = 0
    i = 0
    x = len(array)

for i in range (3):
    userNumber = int(input("please enter the numbers you saw IN ORDER(press Enter when finished): "))

    #if they enter the right number, they gain a score and get to move to the next level
    while userNumber != array[i]:
        print ("the numbers where: ", array[i])
        incorrect = incorrect +1
        ("you got ", incorrect, "wrong")

    if userNumber == array[i]:
        score = correct + 100
        i = i + 1
    print ("you have ",score, "points")
levelOne ()

玩游戏时显示的内容示例：

请按顺序输入您看到的数字（完成后按enter键）：58

请按顺序输入您看到的数字（完成后按enter键）：84

请按顺序输入您看到的数字（完成后按enter键）：44

你得了100分

您尚未初始化变量“不正确”。它将抛出一个名称错误

不需要while循环。将“while”替换为“if”语句

分数=分数+1。这里不需要正确的变量。（除非你想告诉玩家他们答对了多少个数字。在这种情况下，初始化correct=0。然后每当玩家的答案正确时，增加correct的计数：correct+=1

与其使用第二个“if”语句检查用户输入的数字是否正确，不如使用“else”语句

以下是固定代码：

    import random
    array = []

    #this appends three random numbers into an empty array
    for i in range(3):
        randomNumber = random.randint(0,100)
        array.append(randomNumber)

    # this function displays the random number for 1250 milliseconds
    def randomNumberDisplay():
        import tkinter as tk
        root = tk.Tk()
        root.title("info")
        tk.Label(root, text=array).pack()
        # time in ms
        root.after(1250, lambda: root.destroy())
        root.mainloop()   
    randomNumberDisplay()


    #this function requires the user to enter the numbers displayed.
    score = 0
    def levelOne ():
        incorrect = 0
        x = len(array)
        incorrect = 0
        for i in range (3):
            userNumber = int(input("please enter the numbers you saw IN ORDER(press Enter when finished): "))

        #if they enter the right number, they gain a score and get to move to the next level
        if userNumber != array[i]:
            print ("the numbers where: ", array[i])
            incorrect = incorrect +1
            print("you got ", incorrect, "wrong")

        else:
            score = score + 100
            i = i + 1
            print ("you have ",score, "points")
    levelOne ()

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谢谢，我现在看到了我的错误，但我希望程序检查输入的每个数字是否与数组[i]中的数字相同。对于每个错误的数字，“不正确”应该增加1。对于每个正确的数字，分数应该增加100。我只是在努力使评分系统正确。