Python 在django admin中上载后提示文件下载

我有一个django管理页面，用户正在上传一个文件，数据在内存中读取，而不实际存储文件

根据内容，在磁盘上生成一个新文件。在调用

save\u model

之前，所有这些都在

clean

方法中发生。下面是生成输出文件的方法

def clean(self):
    obj = Parser()
    cleaned_data = super(MyMethodAdminForm, self).clean()
    input_data = self.request.FILES['file_name'].read().split('\n')
    base_file = settings.MEDIA_ROOT + "/uploads/" + cleaned_data.get('file_name').name

    # This is the output file, which needs to be downloaded
    output_filename = base_file.replace('.csv', '_output.csv')
    output_list = []

    # Read the file and prepare the output data
    # on the basis of the input data
    for line in input_data:
        data = line.split(",")
        if len(data) > 1:
            dt = obj.get_data()
            current_list = [data[0], data[1]]
        else:
            dt = obj.get_data()
            current_list = [data[0]]
        current_list.append(str(dt))
        output_list.append(current_list)

    # Prepare the file on the basis of the output data
    with open(output_filename, 'a') as outcsv:
        # configure writer to write standard csv file
        writer = csv.writer(outcsv, delimiter=',', quotechar=' ', quoting=csv.QUOTE_MINIMAL, lineterminator='\n')
        for item in output_list:
            if len(item) > 2:
                # Write item to outcsv
                writer.writerow([item[0], item[1], item[2]])
            else:
                writer.writerow([item[0], item[1]])
    return cleaned_data

现在，我的问题是，我必须允许此文件下载，但由于上载域是通过负载平衡器处理的，因此我无法真正提供链接（老实说，这也不是首选方式）。是否有任何方法可以强制提示文件下载

我从下面的两个问题中得到了一些提示，但我不明白我需要把这些

更改标题的东西放在哪里

编辑

经过一点调试后，我尝试按照线程中的建议更新

response\u change

但即使是pdb也没有被呼叫…所以还没有帮助！！：(

全班：

class MyMethodAdminForm(forms.ModelForm):
    class Meta(object):
        model = MyMethod
        fields = ["file_name"]

    def clean(self):
        obj = Parser()
        cleaned_data = super(MyMethodAdminForm, self).clean()
        input_data = self.request.FILES['file_name'].read().split('\n')
        base_file = settings.MEDIA_ROOT + "/uploads/" + cleaned_data.get('file_name').name
        output_filename = base_file.replace('.csv', '_output.csv')
        output_list = []

        # Read the file and prepare the output data
        # on the basis of the input data
        for line in input_data:
            data = line.split(",")
            if len(data) > 1:
                dt = obj.get_data()
                current_list = [data[0], data[1]]
            else:
                dt = obj.get_data()
                current_list = [data[0]]
            current_list.append(str(dt))
            output_list.append(current_list)

        # Prepare the file on the basis of the output data
        with open(output_filename, 'a') as outcsv:
            # configure writer to write standard csv file
            writer = csv.writer(outcsv, delimiter=',', quotechar=' ', quoting=csv.QUOTE_MINIMAL, lineterminator='\n')
            for item in output_list:
                if len(item) > 2:
                    # Write item to outcsv
                    writer.writerow([item[0], item[1], item[2]])
                else:
                    writer.writerow([item[0], item[1]])
        return cleaned_data

---

无论您准备在何处向用户发送响应：

response = HttpResponse(content_type='text/csv')
response['Content-Disposition'] = 'attachment; filename="%s"' % filename
writer = csv.writer(response)
# now write to writer however you want to output your CSV

---

根据调用视图的位置，您可能需要覆盖多种方法。原因是django支持不同类型的管理操作，包括

更改

、

添加

、

删除

。我不确定您使用的是哪种方法，因此您可能必须同时尝试这两种方法。首先，我将尝试覆盖

response\u change

和

response\u add

方法：

class MyMethodAdmin(admin.ModelAdmin):
    form = MyMethodAdminForm

    def return_csv(self):
        response = HttpResponse(content_type='text/csv')
        response['Content-Disposition'] = 'attachment; filename="%s"' % filename
        writer = csv.writer(response)
        writer.writerow(['Django','Admin'])
        return response

    def response_change(self, request, obj):
        return self.return_csv()

    def response_add(self, request, obj):
        return self.return_csv()

---

“…无论您准备在何处向用户发送响应…”这就是我不知道的一点…哪种方法是关键？请看我的更新，在你有

clean

的完整类上。它只包含我添加的

clean

方法，但我需要整个类，包括类名和继承来帮助。你的缩进响应是否改变了意图nal？错误复制粘贴的缺点…已更正

class MyMethodAdmin(admin.ModelAdmin):
    form = MyMethodAdminForm

    def return_csv(self):
        response = HttpResponse(content_type='text/csv')
        response['Content-Disposition'] = 'attachment; filename="%s"' % filename
        writer = csv.writer(response)
        writer.writerow(['Django','Admin'])
        return response

    def response_change(self, request, obj):
        return self.return_csv()

    def response_add(self, request, obj):
        return self.return_csv()