Python 如何将词典插入空词典？

我正在使用BFS算法，我有这个代码的输出

>     for node in graph.keys():
>         print(BFS(graph, node))

输出

{1: 0, 6: 1, 7: 2, 2: 3, 8: 4, 3: 5, 4: 6, 9: 7, 5: 8, 10: 9}
{2: 0, 8: 1, 3: 2, 4: 3, 9: 4, 5: 5, 10: 6, 1: -1, 6: -1, 7: -1}
{3: 0, 4: 1, 9: 2, 5: 3, 10: 4, 1: -1, 2: -1, 6: -1, 7: -1, 8: -1}
{4: 0, 9: 1, 5: 2, 10: 3, 1: -1, 2: -1, 3: -1, 6: -1, 7: -1, 8: -1}
{5: 0, 10: 1, 1: -1, 2: -1, 3: -1, 4: -1, 6: -1, 7: -1, 8: -1, 9: -1}
{6: 0, 7: 1, 2: 2, 8: 3, 3: 4, 4: 5, 9: 6, 5: 7, 10: 8, 1: -1}
{7: 0, 2: 1, 8: 2, 3: 3, 4: 4, 9: 5, 5: 6, 10: 7, 1: -1, 6: -1}
{8: 0, 3: 1, 4: 2, 9: 3, 5: 4, 10: 5, 1: -1, 2: -1, 6: -1, 7: -1}
{9: 0, 5: 1, 10: 2, 1: -1, 2: -1, 3: -1, 4: -1, 6: -1, 7: -1, 8: -1}
{10: 0, 1: -1, 2: -1, 3: -1, 4: -1, 5: -1, 6: -1, 7: -1, 8: -1, 9: -1}

我需要将这些字典添加到一个字典中，如下所示

dic = {
    1: {1: 0, 6: 1, 7: 2, 2: 3, 8: 4, 3: 5, 4: 6, 9: 7, 5: 8, 10: 9},
    2: {2: 0, 8: 1, 3: 2, 4: 3, 9: 4, 5: 5, 10: 6, 1: -1, 6: -1, 7: -1},
    3: {3: 0, 4: 1, 9: 2, 5: 3, 10: 4, 1: -1, 2: -1, 6: -1, 7: -1, 8: -1},
    4: {4: 0, 9: 1, 5: 2, 10: 3, 1: -1, 2: -1, 3: -1, 6: -1, 7: -1, 8: -1},
    5: {5: 0, 10: 1, 1: -1, 2: -1, 3: -1, 4: -1, 6: -1, 7: -1, 8: -1, 9: -1},
    6: {6: 0, 7: 1, 2: 2, 8: 3, 3: 4, 4: 5, 9: 6, 5: 7, 10: 8, 1: -1},
    7: {7: 0, 2: 1, 8: 2, 3: 3, 4: 4, 9: 5, 5: 6, 10: 7, 1: -1, 6: -1},
    8: {8: 0, 3: 1, 4: 2, 9: 3, 5: 4, 10: 5, 1: -1, 2: -1, 6: -1, 7: -1},
    9: {9: 0, 5: 1, 10: 2, 1: -1, 2: -1, 3: -1, 4: -1, 6: -1, 7: -1, 8: -1},
   10: {10: 0, 1: -1, 2: -1, 3: -1, 4: -1, 5: -1, 6: -1, 7: -1, 8: -1, 9: -1}
}

我假设创建一个空字典，并将节点添加为键，将代码的输出添加为值。但它不起作用

谢谢

试试这个：

dic = {}
for num, node in enumerate(graph.keys()):
    dic[num] = BFS(graph, node)
    print(BFS(graph, node))

---

仅使用听写理解：

{node:BFS(graph, node) for node in graph.keys()}

res = {i + 1: BFS(graph, node) for i, node in enumerate(graph.keys())}

---

您可以应用

enumerate（）

来使用dict comprehension生成

dict

：

{node:BFS(graph, node) for node in graph.keys()}

res = {i + 1: BFS(graph, node) for i, node in enumerate(graph.keys())}

---

---

哎哟，我错过了你想用

节点

作为dict键的机会。@Andrei已经用代码回答了这个问题。

完美兄弟，谢谢。我能问你点别的吗？我在这本词典中应用了pandas，但是输出的行看起来是无序的（1,6,3,5,4等等），你知道如何排序吗？@Andres，将

graph.keys（）

替换为

sorted（graph.keys（））

@Andres dict不能保证顺序，所以你需要对pandas行进行排序，你是对的，我必须在pandas中进行排序。谢谢