在mac上打开python上的文本文件

我正试图在mac上用python编写一个程序，允许用户搜索数据库。我无法打开、查找或读取所附的文本文件

我使用了：

import os
with open('a3-example-data.txt', 'r') as f:
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            f.seek(0)
            f.readline()
            for line in f:
                if 'Time Taken' in line:
                    print line
                    print ' '.join(line.split())
f.close()

及

---

但不断收到错误信息。请帮助我：（

您的代码在许多方面都有缺陷，我猜错误是在您返回到主迭代时出现的，而您返回到

0

，使主迭代不同步

# you do not need the os module in your code. Useless import
import os

with open('a3-example-data.txt', 'r') as f:
    ### the f.readline() is only making you skip the first line.
    ### Are you doing it on purpose?
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            ### seeking back to zero,
            f.seek(0)
            ### skipping a line
            f.readline()
            ### iterating over the file again, 
            ### while shadowing the current iteration
            for line in f:
                if 'Time Taken' in line:
                    print line
                    print ' '.join(line.split()) # why are you joining what you just split?
       ### and returning to the main iteration which will get broken
       ### because of the seek(0) within
       ### does not make much sense.

### you're using the context manager, so once you exit the `with` block, the file is closed
### no need to double close it!
f.close()

因此，在不了解您的目标的情况下，以下是我对您的算法的看法：

import os
with open('a3-example-data.txt', 'r') as f:
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            break
    f.seek(0)
    f.readline()
    for line in f:
         if 'Time Taken' in line:
             print line

---

您的代码在很多方面都有缺陷，我猜当您返回到主迭代时会出现错误，而您返回到

0

，使主迭代不同步

# you do not need the os module in your code. Useless import
import os

with open('a3-example-data.txt', 'r') as f:
    ### the f.readline() is only making you skip the first line.
    ### Are you doing it on purpose?
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            ### seeking back to zero,
            f.seek(0)
            ### skipping a line
            f.readline()
            ### iterating over the file again, 
            ### while shadowing the current iteration
            for line in f:
                if 'Time Taken' in line:
                    print line
                    print ' '.join(line.split()) # why are you joining what you just split?
       ### and returning to the main iteration which will get broken
       ### because of the seek(0) within
       ### does not make much sense.

### you're using the context manager, so once you exit the `with` block, the file is closed
### no need to double close it!
f.close()

因此，在不了解您的目标的情况下，以下是我对您的算法的看法：

import os
with open('a3-example-data.txt', 'r') as f:
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            break
    f.seek(0)
    f.readline()
    for line in f:
         if 'Time Taken' in line:
             print line

---

您的代码在很多方面都有缺陷，我猜当您返回到主迭代时会出现错误，而您返回到

0

，使主迭代不同步

# you do not need the os module in your code. Useless import
import os

with open('a3-example-data.txt', 'r') as f:
    ### the f.readline() is only making you skip the first line.
    ### Are you doing it on purpose?
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            ### seeking back to zero,
            f.seek(0)
            ### skipping a line
            f.readline()
            ### iterating over the file again, 
            ### while shadowing the current iteration
            for line in f:
                if 'Time Taken' in line:
                    print line
                    print ' '.join(line.split()) # why are you joining what you just split?
       ### and returning to the main iteration which will get broken
       ### because of the seek(0) within
       ### does not make much sense.

### you're using the context manager, so once you exit the `with` block, the file is closed
### no need to double close it!
f.close()

因此，在不了解您的目标的情况下，以下是我对您的算法的看法：

import os
with open('a3-example-data.txt', 'r') as f:
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            break
    f.seek(0)
    f.readline()
    for line in f:
         if 'Time Taken' in line:
             print line

---

您的代码在很多方面都有缺陷，我猜当您返回到主迭代时会出现错误，而您返回到

0

，使主迭代不同步

# you do not need the os module in your code. Useless import
import os

with open('a3-example-data.txt', 'r') as f:
    ### the f.readline() is only making you skip the first line.
    ### Are you doing it on purpose?
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            ### seeking back to zero,
            f.seek(0)
            ### skipping a line
            f.readline()
            ### iterating over the file again, 
            ### while shadowing the current iteration
            for line in f:
                if 'Time Taken' in line:
                    print line
                    print ' '.join(line.split()) # why are you joining what you just split?
       ### and returning to the main iteration which will get broken
       ### because of the seek(0) within
       ### does not make much sense.

### you're using the context manager, so once you exit the `with` block, the file is closed
### no need to double close it!
f.close()

因此，在不了解您的目标的情况下，以下是我对您的算法的看法：

import os
with open('a3-example-data.txt', 'r') as f:
    f.readline()
    for line in f:
        if 'Sample Text' in line:
            print "I have found it"
            break
    f.seek(0)
    f.readline()
    for line in f:
         if 'Time Taken' in line:
             print line

---

这个错误消息，是什么？还有，我不确定你为什么认为第二个代码段会工作，它有语法错误。这个错误消息，它是什么？还有，我不确定你为什么认为第二个代码段会工作，它有语法错误。这个错误消息，它是什么？还有，我不确定你为什么认为第二个代码段会工作，它有语法错误。这个错误消息是什么？而且，我不知道你为什么认为第二个代码段会工作，它有语法错误。