在Python 2.7中创建套接字时出错

我对套接字或网络编程非常陌生。我只是想创建一个套接字，但是python给了我回溯。 我在Ubuntu12上使用Python2.7

我的代码：

import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'OK'

回溯是：

    Error in sys.excepthook:
Traceback (most recent call last):
  File "/usr/lib/python2.7/dist-packages/apport_python_hook.py", line 66, in apport_excepthook
    from apport.fileutils import likely_packaged, get_recent_crashes
  File "/usr/lib/python2.7/dist-packages/apport/__init__.py", line 1, in <module>
    from apport.report import Report
  File "/usr/lib/python2.7/dist-packages/apport/report.py", line 12, in <module>
    import subprocess, tempfile, os.path, urllib, re, pwd, grp, os
  File "/usr/lib/python2.7/urllib.py", line 26, in <module>
    import socket
  File "/home/ans/Desktop/python_p/socket.py", line 2, in <module>
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
AttributeError: 'module' object has no attribute 'AF_INET'

Original exception was:
Traceback (most recent call last):
  File "socket.py", line 1, in <module>
    import socket
  File "/home/ans/Desktop/python_p/socket.py", line 2, in <module>
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
AttributeError: 'module' object has no attribute 'AF_INET'

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您将程序文件命名为socket.py，因此将导入此文件，而不是标准库模块。重命名文件，删除任何socket.pyc并重试。

您将程序文件命名为socket.py，因此将导入此文件，而不是标准库模块。重命名文件，删除任何socket.pyc并重试