Python 使用lxml解析期间解析外部未解析实体
在使用lxml解析期间,如何解析外部未解析的实体 下面是我的代码示例:Python 使用lxml解析期间解析外部未解析实体,python,lxml,doctype,dtd-parsing,Python,Lxml,Doctype,Dtd Parsing,在使用lxml解析期间,如何解析外部未解析的实体 下面是我的代码示例: import io from lxml import etree content = b"""\ <?xml version="1.0"?> <!DOCTYPE sample [ <!NOTATION jpeg SYSTEM "image/jpeg"> <!ENTITY ref1 SYSTEM "python-logo-small.jpg" NDATA jpeg> <!EL
import io
from lxml import etree
content = b"""\
<?xml version="1.0"?>
<!DOCTYPE sample [
<!NOTATION jpeg SYSTEM "image/jpeg">
<!ENTITY ref1 SYSTEM "python-logo-small.jpg" NDATA jpeg>
<!ELEMENT sample EMPTY>
<!ATTLIST sample src ENTITY #REQUIRED>
]>
<sample src="ref1"/>
"""
parser = etree.XMLParser(dtd_validation=True, resolve_entities=True)
doc = etree.parse(io.BytesIO(content), parser=parser)
print(etree.tostring(doc))
但我有同样的结果
或者,我想自己解决这些实体。为此,我尝试以这种方式列出实体:
for entity in doc.docinfo.internalDTD.iterentities():
msg_fmt = "{entity.name!r}, {entity.content!r}, {entity.orig!r}"
print(msg_fmt.format(entity=entity))
但我只得到实体和符号的名称,而不是实体的定义:
'ref1', 'jpeg', None
如何访问实体的定义?包含未解析实体的XML文档看起来正常。但是,未解析的实体不会以您似乎期望的方式得到解析。如果要在已解析的输出中查看
,请使用内部(已解析)实体
例如:
import io
from lxml import etree
content = b"""\
<?xml version="1.0"?>
<!DOCTYPE sample [
<!ENTITY ref1 "python-logo-small.jpg">
<!ELEMENT sample EMPTY>
<!ATTLIST sample src CDATA #REQUIRED>
]>
<sample src="&ref1;"/>
"""
parser = etree.XMLParser(dtd_validation=True, resolve_entities=True)
doc = etree.parse(io.BytesIO(content), parser=parser)
print(etree.tostring(doc))
输出:
python-logo-small.jpg
好的,不可能“解析”外部未解析实体,但我们可以列出它们:
import io
import xml.sax
content = b"""\
<?xml version="1.0"?>
<!DOCTYPE sample [
<!NOTATION jpeg SYSTEM "image/jpeg">
<!ENTITY ref1 SYSTEM "python-logo-small.jpg" NDATA jpeg>
<!ELEMENT sample EMPTY>
<!ATTLIST sample src ENTITY #REQUIRED>
]>
<sample src="ref1"/>
"""
class MyDTDHandler(xml.sax.handler.DTDHandler):
def __init__(self):
pass
def unparsedEntityDecl(self, name, publicId, systemId, ndata):
print(dict(name=name, publicId=publicId, systemId=systemId, ndata=ndata))
xml.sax.handler.DTDHandler.unparsedEntityDecl(self, name, publicId, systemId, ndata)
parser = xml.sax.make_parser()
parser.setDTDHandler(MyDTDHandler())
parser.parse(io.BytesIO(content))
工作已经完成。不幸的是,我不是XML内容的作者,因此无法修改它。有没有办法列出内部实体?有关于xml.sax.handler的例子吗?
xsl = etree.XML('''\
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="utf-8" omit-xml-declaration="yes"/>
<xsl:template match="sample">
<xsl:value-of select="unparsed-entity-uri(@src)"/>
</xsl:template>
</xsl:stylesheet>
''')
transform = etree.XSLT(xsl)
result = transform(doc)
print result
python-logo-small.jpg
import io
import xml.sax
content = b"""\
<?xml version="1.0"?>
<!DOCTYPE sample [
<!NOTATION jpeg SYSTEM "image/jpeg">
<!ENTITY ref1 SYSTEM "python-logo-small.jpg" NDATA jpeg>
<!ELEMENT sample EMPTY>
<!ATTLIST sample src ENTITY #REQUIRED>
]>
<sample src="ref1"/>
"""
class MyDTDHandler(xml.sax.handler.DTDHandler):
def __init__(self):
pass
def unparsedEntityDecl(self, name, publicId, systemId, ndata):
print(dict(name=name, publicId=publicId, systemId=systemId, ndata=ndata))
xml.sax.handler.DTDHandler.unparsedEntityDecl(self, name, publicId, systemId, ndata)
parser = xml.sax.make_parser()
parser.setDTDHandler(MyDTDHandler())
parser.parse(io.BytesIO(content))
{'systemId': u'python-logo-small.jpg', 'ndata': u'jpeg', 'publicId': None, 'name': u'ref1'}