Python 将具有多个状态的QtQuick项目保存到.png文件
我正在尝试将具有多个状态的可视项保存为.png图像(每个状态一个png) 我在onStateChanged信号处理程序中调用该项的grabToImage()方法,但图像仅在发生最后一次状态更改后保存,仅创建一个与该项的最后一次设置状态相对应的图像 我还尝试在python端调用saveToFile(),但这会导致运行时错误(请参阅python代码中的注释) grab_states.pyPython 将具有多个状态的QtQuick项目保存到.png文件,python,qml,qtquick2,pyside2,Python,Qml,Qtquick2,Pyside2,我正在尝试将具有多个状态的可视项保存为.png图像(每个状态一个png) 我在onStateChanged信号处理程序中调用该项的grabToImage()方法,但图像仅在发生最后一次状态更改后保存,仅创建一个与该项的最后一次设置状态相对应的图像 我还尝试在python端调用saveToFile(),但这会导致运行时错误(请参阅python代码中的注释) grab_states.py from PySide2.QtCore import QUrl from PySide2.QtWidgets i
from PySide2.QtCore import QUrl
from PySide2.QtWidgets import QApplication
from PySide2.QtQuick import QQuickView
app = QApplication([])
view = QQuickView()
view.setSource(QUrl('grab_states.qml'))
view.show()
rect = view.rootObject()
rect.setState('off')
rect.setState('on')
# RuntimeError: Internal C++ object (PySide2.QtQuick.QQuickItemGrabResult) already deleted.
# rect.grabToImage().data().saveToFile(rect.property('state') + ".png")
app.exec_()
from PySide2 import QtCore, QtGui, QtQuick
if __name__ == '__main__':
import sys
app = QtGui.QGuiApplication(sys.argv)
view = QtQuick.QQuickView()
view.setSource(QtCore.QUrl('grab_states.qml'))
view.show()
rect = view.rootObject()
rect.setProperty("currentIndex", 0)
sys.exit(app.exec_())
grab_states.qml
import QtQuick 2.0
Rectangle {
id: rect
width: 100
height: 100
color: "black"
states: [
State {name: "off"; PropertyChanges{target: rect; color: "red"}},
State {name: "on"; PropertyChanges{target: rect; color: "green"}}
]
onStateChanged: {
print('stateChaged: ' + state)
rect.grabToImage(function(result){
print("saveToFile: " + rect.state);
result.saveToFile(state + '.png');
}
)
}
}
import QtQuick 2.0
Rectangle {
id: rect
width: 100
height: 100
color: "black"
property int currentIndex: -1
onCurrentIndexChanged: if(currentIndex >= 0 && currentIndex < states.length) state = states[currentIndex].name
states: [
State {name: "off"; PropertyChanges{target: rect; color: "red"}},
State {name: "on"; PropertyChanges{target: rect; color: "green"}}
]
onStateChanged: {
rect.grabToImage(function(result){
result.saveToFile(state + ".png");
currentIndex+= 1;
console.log(filename);
})
}
}
saveToFile函数的调用是预期的两倍,但只是在所有状态更改发生之后,所以我只得到一个显示最后一个状态并覆盖第一个图像的图像。如果我使用不同的文件名来防止覆盖,那么我会得到两个图像,都显示最终状态
如何为项目的每个状态保存相应的图像?您有两个错误:
- 您正在更改状态,但未确保已保存图像
- 通过执行上述操作,状态值将在grabToImage中更新,并将指向以前的状态
from PySide2.QtCore import QUrl
from PySide2.QtWidgets import QApplication
from PySide2.QtQuick import QQuickView
app = QApplication([])
view = QQuickView()
view.setSource(QUrl('grab_states.qml'))
view.show()
rect = view.rootObject()
rect.setState('off')
rect.setState('on')
# RuntimeError: Internal C++ object (PySide2.QtQuick.QQuickItemGrabResult) already deleted.
# rect.grabToImage().data().saveToFile(rect.property('state') + ".png")
app.exec_()
from PySide2 import QtCore, QtGui, QtQuick
if __name__ == '__main__':
import sys
app = QtGui.QGuiApplication(sys.argv)
view = QtQuick.QQuickView()
view.setSource(QtCore.QUrl('grab_states.qml'))
view.show()
rect = view.rootObject()
rect.setProperty("currentIndex", 0)
sys.exit(app.exec_())
*.qml
import QtQuick 2.0
Rectangle {
id: rect
width: 100
height: 100
color: "black"
states: [
State {name: "off"; PropertyChanges{target: rect; color: "red"}},
State {name: "on"; PropertyChanges{target: rect; color: "green"}}
]
onStateChanged: {
print('stateChaged: ' + state)
rect.grabToImage(function(result){
print("saveToFile: " + rect.state);
result.saveToFile(state + '.png');
}
)
}
}
import QtQuick 2.0
Rectangle {
id: rect
width: 100
height: 100
color: "black"
property int currentIndex: -1
onCurrentIndexChanged: if(currentIndex >= 0 && currentIndex < states.length) state = states[currentIndex].name
states: [
State {name: "off"; PropertyChanges{target: rect; color: "red"}},
State {name: "on"; PropertyChanges{target: rect; color: "green"}}
]
onStateChanged: {
rect.grabToImage(function(result){
result.saveToFile(state + ".png");
currentIndex+= 1;
console.log(filename);
})
}
}
导入QtQuick 2.0
长方形{
id:rect
宽度:100
身高:100
颜色:“黑色”
属性int currentIndex:-1
onCurrentIndexChanged:if(currentIndex>=0&¤tIndex
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