Python 从数组的一个元素中查找所有匹配的单词，保留这些单词，但删除元素'；没有这些词的是什么

我试图删除数组/json中的所有元素，这些元素中没有字符串中的所有单词。例如：

要找到的话：世界坚持住

Array [
    {
       "title" : "Hold On World",
       "artist": "some guy"
    },
    { 
       "title" : "World, Hold On",
       "artist": "some guy"
    },
    {
       "title" : "World Hold On Now",
       "artist": "some guy"  
    },
    {
       "title" : "World Is Ending",
       "artist": "some guy"
    }
 ]

因此，对于这个数组，前三个元素应该被保存，但最后一个元素应该被删除，我已经尝试过这样的方法：

def removeNonMatches(data, title):
    old = title.split(' ')
    new = '|'.join(old)
    p = re.compile(new, re.I)
    for x in data:
       if bool(p.search(r"\b("+p+")\b", x['title'], re.IGNORECASE)) == False:
            data.remove(x)
    return data

data = [
     {
       "title" : "Hold On World",
       "artist": "some guy"
    },
    { 
       "title" : "World, Hold On",
       "artist": "some guy"
    },
    {
       "title" : "World Hold On Now",
       "artist": "some guy"  
    },
    {
       "title" : "World Is Ending",
       "artist": "some guy"
    }
]

title = 'World Hold On'

new_data = removeNonMatches(data, title)

你可以用

data = [
    {
       "title" : "Hold On World",
       "artist": "some guy"
    },
    { 
       "title" : "World, Hold On",
       "artist": "some guy"
    },
    {
       "title" : "World Hold On Now",
       "artist": "some guy"  
    },
    {
       "title" : "World Is Ending",
       "artist": "some guy"
    }
 ]
words = ["World", "Hold", "On"]

keep =  [item for item in data
         if all(word in item["title"] for word in words)]
print(keep)

产生

[{'title': 'Hold On World', 'artist': 'some guy'}, 
 {'title': 'World, Hold On', 'artist': 'some guy'}, 
 {'title': 'World Hold On Now', 'artist': 'some guy'}]

---

要使用大写和小写单词，请使用

words = ["world", "hold", "on"]
keep =  [item for item in data
         if all(word in item["title"].lower() for word in words)]

---

查看

all（）

。这很有效，谢谢，我得到了不同的结果，但是我认为这与调用服务器的结果有关。非常感谢。