Python guizero Raspberry Pi:按钮->命令序列问题

要求：按下guizero应用程序上的按钮应首先设置一个文本值，然后在此处执行一个简单的时间功能；最初是一个子流程；执行功能后，应显示结果文本

#!/usr/bin/python3
# -*- coding: utf-8 -*-

from guizero import App, PushButton, Text
import subprocess
import time

# Action you would like to perform
def counter0():
    global s0
    text0.value = int(text0.value) + 1  # works
    text1.value = s0                    # works

def counter1():
    global s0
    text1.value = s0       # display a status value - but does not (!)
    time.sleep(1)          # originally a subprocess is called here; works
    text1.value = "ready"  # only diplays this after a delay

s0="start something after pressing butt1"

app = App("Hello world", layout="grid")

text0 = Text(app, text="1", align="left", grid=[0,1])
text1 = Text(app, text=s0, align="left",grid=[0,8] )
butt1 = PushButton(app, text="Button", command=counter1, align="left", grid=[0,2])
text0.repeat(10000, counter0)  # Schedule call to counter() every 1000ms

app.display()

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很可能我不理解guizero背后的想法。有什么办法来管理这些需求吗？

如果我正确理解您的问题，您的具体问题如下：

    text1.value = s0       # display a status value - but does not (!)

这不起作用，因为guizero框架正在同步执行函数：在函数返回之前，不会执行其他代码（包括更新显示的代码）

如果您想：

在使用子流程运行命令之前显示消息 运行一些命令 在命令完成后显示消息 然后你们需要重写你们的逻辑，这样你们的应用程序就不会等待“计数器1”完成了。异步运行代码的一个选项是在单独的线程中运行代码。例如：

from guizero import App, PushButton, Text
import threading
import time


# Action you would like to perform
def counter0():
    global s0
    text0.value = int(text0.value) + 1  # works
    text1.value = s0                    # works


def run_command():
    time.sleep(1)          # originally a subprocess is called here; works
    text1.value = "ready"  # only diplays this after a delay


def counter1():
    global s0
    text1.value = "Running command..."
    threading.Thread(target=run_command).start()


s0 = "start something after pressing butt1"

app = App("Hello world", layout="grid")

text0 = Text(app, text="1", align="left", grid=[0, 1])
text1 = Text(app, text=s0, align="left", grid=[0, 8])
butt1 = PushButton(app, text="Button", command=counter1,
                   align="left", grid=[0, 2])
text0.repeat(10000, counter0)

app.display()

运行上述代码将提供以下行为：

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谢谢你，拉尔克斯，给了我一个快速而有用的回答。这正是我想要的。我想看看其他的方法，但只是为了满足我的好奇心。你建议的方法对我来说简单易懂，而且很短。顺便说一句：漂亮的动画gif；C