Python 如何在包含数字和字符串的列表中添加数字
假设我有一个如下列表:Python 如何在包含数字和字符串的列表中添加数字,python,list,Python,List,假设我有一个如下列表: ExampleList = [2,4,7,4,2,"randomword",23,42,2,1,4,-53,"newrandomword",32,5,2,3] 我如何只添加数字 您可以使用以下生成器表达式,它将在列表中添加所有int: l = [2,4,7,4,2,"randomword",23,42,2,1,4,-53,"newrandomword",32,5,2,3] sum(i for i in l if isinstance(i,int)) # 80 您还可
ExampleList = [2,4,7,4,2,"randomword",23,42,2,1,4,-53,"newrandomword",32,5,2,3]
我如何只添加数字 您可以使用以下生成器表达式,它将在列表中添加所有
int
:
l = [2,4,7,4,2,"randomword",23,42,2,1,4,-53,"newrandomword",32,5,2,3]
sum(i for i in l if isinstance(i,int))
# 80
您还可以使用函数
filter()
:
这将处理所有数字:)
通过编程,您可以总结如下:
l = [2,4,7,4,2,"randomword",23,42,2,1,4,-53,"newrandomword",32,5,2,3]
s=0
for i in l:
try:
s+=int(i)
except ValueError:
print('not a rumber')
print('sum of number is:',s)
>>> import numbers
>>> x
[2, 4, 7, 4, 2, 'randomword', 23, 42, 2, 1, 4, -53, 'newrandomword', 32, 5, 2, 3, 1.02]
>>> sum(y for y in x if isinstance(y, numbers.Number))
81.02
l = [2,4,7,4,2,"randomword",23,42,2,1,4,-53,"newrandomword",32,5,2,3]
s=0
for i in l:
try:
s+=int(i)
except ValueError:
print('not a rumber')
print('sum of number is:',s)