如何确保int在while循环中只扣除一次（python3）

所以我创建了一个项目“公牛和奶牛”。其中，计算机随机生成一个四位数字。然后用户必须猜测一个四位数的数字。如果数字是计算机中的4位数字，那么你得到一头公牛，如果不是，那么你得到一头奶牛。程序运行，直到用户获得所有四位数字

我以为它在工作，直到我把一个数字的四个放进去，它还是接受了。我试着添加一个if语句，但是现在它不计算任何正确的数字

import random

number = random.choice(range(1000, 9999))
number = str(number)
print(number)

flag = True
while flag:
    cow = 0
    bull = 0
    user = input('Number ')
    user = str(user)
    for item in user:
        x = number.count(item)
        y = int(item)
        if y <= x:
            bull += 1
        else:
            cow += 1


    print(f"You have {bull} bulls, and {cow} cows!")
    if bull == 4:
        print(f'The computers number is {number}')
        flag = False
    else:
        print("Guess again")

随机导入
数字=随机选择（范围（10009999））
编号=str（编号）
打印（数字）
flag=True
而国旗：
奶牛=0
布尔=0
用户=输入（'Number'）
user=str（用户）
对于用户中的项目：
x=数量。计数（项目）
y=int（项目）
如果y复制
编号
。然后，当用户猜对一个数字时，将其从该副本中删除。这样，如果他们猜测数字的次数超过数字中出现的次数，那么额外的猜测就不会被复制

此副本应该是一个列表，以便您可以使用其
remove（）
方法

while True:
    cow = 0
    bull = 0
    user = input('Number ')
    num_list = list(number)
    for item in user:
        if item in num_list:
            bull += 1
            num_list.remove(item)
        else:
            cow += 1

    print(f"You have {bull} bulls, and {cow} cows!")
    if bull == 4:
        print(f'The computer's number is {number}')
        break
    else:
        print("Guess again")

根据之前的建议和我个人的想法，我做了一些改变。进行一点错误检查，以确保此人输入了一个数字，并记录此人的猜测，以便多次猜测同一个数字不会对他们不利

import random

orig_number = random.choice(range(1000, 9999))
copy_number = str(orig_number)
cows = 0
bulls = 0
guesses = []

def convert_to_int(data):
    if data is None:
        return False

    try:
        id = int(data)
    except ValueError:
        return False
    else:
        return True

while True:
    guess = input("Guess a number > ")
    if not convert_to_int(str(guess)[0]):
        print("That was not a number")
        continue

    if str(guess)[0] in guesses:
        print("You already guessed that number")
        continue
    elif str(guess)[0] in copy_number:
        print("Good guess, you get a bull")
        bulls += 1
        copy_number = copy_number.replace(str(guess)[0],'')
    else:
        print("Too bad, you get a cow")
        cows += 1

    guesses.append(str(guess)[0])

    print("You have {} cows and {} bulls".format(cows,bulls))
    if len(copy_number) == 0: break
    
print("Congratulations!  You guessed all the numbers.  The original number was {}".format(orig_number))

从测试运行中：

Guess a number > a
That was not a number
Guess a number > -   
That was not a number
Guess a number > 9   
Too bad, you get a cow     
You have 1 cows and 0 bulls
Guess a number > 1
Too bad, you get a cow     
You have 2 cows and 0 bulls
Guess a number > 4
Too bad, you get a cow     
You have 3 cows and 0 bulls
Guess a number > 3
Too bad, you get a cow     
You have 4 cows and 0 bulls
Guess a number > 6
Too bad, you get a cow
You have 5 cows and 0 bulls
Guess a number > 5
Good guess, you get a bull
You have 5 cows and 1 bulls
Guess a number > 7
Too bad, you get a cow
You have 6 cows and 1 bulls
Guess a number > 8
Too bad, you get a cow
You have 7 cows and 1 bulls
Guess a number > 9
You already guessed that number
Guess a number > 0
Good guess, you get a bull
You have 7 cows and 2 bulls
Guess a number > 1
You already guessed that number
Guess a number > 2
Good guess, you get a bull
You have 7 cows and 3 bulls
Congratulations!  You guessed all the numbers.  The original number was 2055

你能解释一下你所说的“我刚把一个数字的四个放进去，它还是接受了”是什么意思吗？给出具体的测试用例和输出。为了帮助我理解，假设数字是“1 1 3 4”，用户输入“2 1 1 1 1”，程序输出应该是什么？我看不出将项目整数值与数字中项目的出现次数进行比较有什么关系？您可能需要检查数字中是否包含每个数字。当用户的数字与数字中的某个数字匹配时，请将其从数字中删除，以便无法再次计数。为什么要执行
user=str（user）
？这已经是一个字符串了。它工作得很好，早些时候我尝试过一个类似的概念，但最终失败了！谢谢你的回答。