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使用openpyxl在Python中读取行数据_Python_Python 3.x_List_Openpyxl - Fatal编程技术网

使用openpyxl在Python中读取行数据

使用openpyxl在Python中读取行数据,python,python-3.x,list,openpyxl,Python,Python 3.x,List,Openpyxl,我试图以python的格式[[a,b],[c,d],…]获取一个列表 例如,对于excel中的以下两列: R1 R2 1 2 6 2 0 9 3 2 4 1 5 6 我应该得到一个列表=[[1,2],[6,2],[0,9],[3,2],[4,1],[5,6]] 我的代码如下所示: R = [] # iterate over column for col in r

我试图以python的格式[[a,b],[c,d],…]获取一个列表

例如,对于excel中的以下两列:

     R1   R2
     1    2
     6    2
     0    9
     3    2
     4    1
     5    6
我应该得到一个列表=[[1,2],[6,2],[0,9],[3,2],[4,1],[5,6]]

我的代码如下所示:

    R = []
    # iterate over column
    for col in range(min_column+3, max_column+1): #location of the data
    # u_need reads in the resource needed for each activity
      u_need = []
      # iterate over row
      for row in range(2, max_row+1): #row 1 is not included
         # loop until blank space is encountered
         if (sheet.cell(row,col).value is not None):
             u_need.append(sheet.cell(row,col).value);

      R.append(u_need)

    print(f'R = {R}')
但结果给了我这样的东西:

    R = [[1, 6, 0, 3, 4, 5], [2, 2, 9, 2, 1, 6]]

有没有办法改变这个?任何帮助都将不胜感激!谢谢

我正在使用xlrd软件包阅读excel工作表

import xlrd 

# my own excel sheet location which contains your data  
loc = "a.xlsx"

# opening workbook 
wb = xlrd.open_workbook(loc) 
# selecting the first worksheet
sheet = wb.sheet_by_index(0) 
lst = []
# not including the first row
for i in range(1,sheet.nrows):
    dummy = []
    for j in range(sheet.ncols):
        # appending the columns with the same row to dummy list
        dummy.append(sheet.cell_value(i, j))
    # appending the dummy list to the main list
    lst.append(dummy)
print(f"lst = {lst}") # output  lst = [[1.0, 2.0], [6.0, 2.0], [0.0, 9.0], [3.0, 2.0], [4.0, 1.0], [5.0, 6.0]]

非常感谢。我在使用openpyxl时得到了它。我认为与我的第一个代码不同的是,我使用循环遍历行之前的列。这就是为什么读取的数据是按列的。非常感谢你!!