Python 使用cdk获取两个分支（codecommit）之间的所有CommitID

我想得到两个分支之间的所有佣金，但我只得到它们之间的第一个和最后一个佣金

这就是我到目前为止的收获：

difference = client.get_differences(
        repositoryName=repo_name,
        beforeCommitSpecifier=main_branch_name,
        afterCommitSpecifier=dev_branch_name
    )
print("difference between branch "+ dev_branch_name + " and "+main_branch_name )

print(difference)
differences = difference['differences']
for diff in differences:
 print("diff")
 print("afterBlob")
 if 'afterBlob' in diff:
   after_or_before_blob = diff['afterBlob']
   if 'beforeBlob' in diff:
            after_or_before_blob = diff['beforeBlob']
        print(after_or_before_blob['blobId'])

        blob = client.get_blob(
            repositoryName=repo_name,
            blobId=after_or_before_blob['blobId']
        )
        print("after_blob 1:")
        print(blob)

我还尝试使用git解决这个问题，例如git diff，但这段代码应该放在AWS Lambda中，git remote codecommit对我不起作用

---

什么能解决我的问题？

我找到了一个适合我需要的答案，尽管有点慢

我在错误的地方寻找答案。差异只是显示文件中的差异，而不是提交本身

因此，我递归地使用GetCommit和给定的ParentId

    def get_list_of_commits(self, client, main_commit_id, repo_name, list_commit_ids=[], list_commits=[]):
        commit_main = client.get_commit(
            repositoryName=repo_name,
            commitId=main_commit_id
        )
        parents = commit_main['commit']['parents']
        for parent in parents:
            self.get_list_of_commits(client, parent, repo_name, list_commit_ids, list_commits)
        commit = commit_main['commit']
        if main_commit_id not in list_commit_ids:
            list_commit_ids.append(main_commit_id)
            list_commits.append(commit)
        return list_commit_ids, list_commits

如果有人知道更好的答案，我会很高兴听到