链接分区的Soundcloud API python问题
关于Soundcloud API指南() 读取100条以上数据的示例如下:链接分区的Soundcloud API python问题,python,pagination,soundcloud,Python,Pagination,Soundcloud,关于Soundcloud API指南() 读取100条以上数据的示例如下: # get first 100 tracks tracks = client.get('/tracks', order='created_at', limit=page_size) for track in tracks: print track.title # start paging through results, 100 at a time tracks = client.get('/tracks',
# get first 100 tracks
tracks = client.get('/tracks', order='created_at', limit=page_size)
for track in tracks:
print track.title
# start paging through results, 100 at a time
tracks = client.get('/tracks', order='created_at', limit=page_size,
linked_partitioning=1)
for track in tracks:
print track.title
我很确定这是错误的,因为我发现“tracks.collection”需要引用,而不仅仅是“tracks”。基于GitHub python soundcloud API wiki,它应该更像这样:
tracks = client.get('/tracks', order='created_at',limit=10,linked_partitioning=1)
while tracks.collection != None:
for track in tracks.collection:
print(track.playback_count)
tracks = tracks.GetNextPartition()
我删除了最后一行的缩进(我认为wiki上有一个错误,它在for循环中,这对我来说没有意义)。这适用于第一个循环。但是,这不适用于连续页面,因为找不到“GetNextPartition()”函数。我尝试了最后一行,如下所示:
tracks = tracks.collection.GetNextPartition()
……但没有成功
也许我把版本弄混了?但在从这里下载版本后,我尝试使用Python 3.4运行此功能:
非常感谢任何帮助 我在SoundCloud开发者论坛上找到了这个解决方案,对任何关心这个问题的人来说都是如此。它从最初的案例(搜索曲目)稍微修改为列出我自己的追随者。诀窍是反复调用client.get函数,将先前返回的“users.next_href”作为指向下一页结果的请求传递。万岁
pgsize=200
c=1
me = client.get('/me')
#first call to get a page of followers
users = client.get('/users/%d/followers' % me.id, limit=pgsize, order='id',
linked_partitioning=1)
for user in users.collection:
print(c,user.username)
c=c+1
#linked_partitioning means .next_href exists
while users.next_href != None:
#pass the contents of users.next_href that contains 'cursor=' to
#locate next page of results
users = client.get(users.next_href, limit=pgsize, order='id',
linked_partitioning=1)
for user in users.collection:
print(c,user.username)
c=c+1